Answer: the length is 11 cm.
The width is 7 cm.
Step-by-step explanation:
Let L represent the length of the rectangular plastic box.
Let W represent the width of the rectangular plastic box.
The area of the rectangular top of the box is 77 square cm. This means that
LW = 77- - - - - - - ;- - - -1
The plastic box has a length 4 cm longer than its width. This means that
L = W + 4
Substituting L = W + 4 into equation 1, it becomes
(W + 4)W = 77
W² + 4W = 77
W² + 4W - 77 = 0
W² + 11W - 7W - 77 = 0
W(W + 11) - 7(W + 11) = 0
W - 7 = 0 or W + 11 = 0
W = 7 or W = - 11
Since the width cannot be negative, then W = 7cm
L = 77/7 = 11 cm
The other factor would be (x + 4). We can find this by using synthetic division. To do this, we must first find the divisor, which would be 9, if we let x - 9 equal to zero and solve for x. Then, for the dividend, we can use the coefficients and constant term values.
<u>9</u>| 1 -5 -36
<u> 9 36</u>
1 4 0
Therefore, the other expression (x + 9) would be (x + 4). Hope this helped!
Answer:
No because upon subtracting x on both sides you obtain a false equation of 4=8.
The problem:
What are x values that satisfy:
x+4=x+8?
Step-by-step explanation:
No number can be substituted into x+4=x+8 to make it true.
There is no number that you can find such that when you add 4 to it will give you the same as adding 8 to it.
Also if you subtract x on both sides you obtain the equation 4=8.
4=8 is not true so x+4=x+8 is never true for any x.
Remember PEMDAS - parentheses, exponents, multiply, divide, add, subtract
because multiply come before subtract, your first step would be 1/2 x 2 = 1
next, you subtract -> 15 - 1 = 14
14 is your answer
Answer:
on the x-axis
Step-by-step explanation:
it is located on the x axis because it is not technically in any quandrant. it is however, on an axis.
