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Bas_tet [7]
3 years ago
6

To model 15 – 11 on a number line, begin at _______ and travel 11 units to the left.

Mathematics
2 answers:
Vadim26 [7]3 years ago
7 0

The answer is 15 cause you start at 15 and go from there


Inga [223]3 years ago
5 0

15 is the correct answer to the fill-in-the-blanks in this problem.

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Please solve and show work
zheka24 [161]

Answer:

Step-by-step explanation:

9. f(g(-n))

g(-n) = -(n²+5) = -n²-5

f(g(-n)) = 2n+1 (-n²-5 )

2n(-n²-5)+1(-n²-5 )

-2n³-10n-n²-5

-2n³-n²-10n-5

n²(-2n-1) +5(2n-1)

(n²+5)(2n-1)

10. (2x+2)(x³+3)

2x(x³+3)+2(x³+3)

2x⁴ + 2x³ +6x +6

2x³(x+1)+6(x+1)

(2x³+6)(x+1

8 0
3 years ago
What is the surface area of a sphere with radius 4?
mario62 [17]

Answer: 64 units

Step-by-step explanation:

Remember, the formula to find surface area given radius is 4\pi r^2. Let's add in the given information:

4pi4^2 =

4pi16

64pi!

Hope this helps, please consider making me Brainliest.

5 0
1 year ago
Marco’s bank statement says that he has an ending balance of $81. What is Marco’s starting balance?
natali 33 [55]

Answer:

$255

Step-by-step explanation:

Using the information provided, in order to find Marco's starting balance we simply need to add all of his transaction costs together. Once we have this value we simply add it to his ending balance amount which will give us the total dollar value of his starting balance.

20 + 22 + 13 + 39 + 34 + 15 + 31 = 174

174 + 81 = $255

Finally, we can see that Marco's starting balance was a total of $255

8 0
3 years ago
Read 2 more answers
Which of the following coordinates would be on the line y = 2x (0, 2) (2, 0) (1, 2) (2, 2) Please explain it!
jolli1 [7]

Answ(0,2)

By putting x 0 and y 2

Step-by-step explanation:

4 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
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