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3 years ago

10

Change this radical to an algebraic expression with fractional exponents 3√a

1 answer:

aliya0001 [1]3 years ago

5 0

$\bf ~\hspace{7em}\textit{rational exponents}
\\\\
a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n}
~\hspace{10em}
% rational negative exponent
a^{-\frac{ n}{ m}} \implies
\cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\sqrt[3]{a}\implies \sqrt[3]{a^1}\implies a^{\frac{1}{3}}$

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The value of a collector’s item is expected to increase exponentially each year. The item is purchased for $500. After 2 years,

Andreyy89

Y = 500(1 + r)^x; where r is the rate and x is the number of years.
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3 years ago

The rule Rx-axis o is applied to the point (-3,-2). Where is the image in the coordinate

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Step-by-step explanation:

Given

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Required

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3 years ago

Read 2 more answers

In order to remove water from a flooded basement, two pumps, each rated at 40 gallons per minute, are used. After half an hour,

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Answer:

3600 gallons of water was removed from the basement.

Step-by-step explanation:

Given:

Rate of each pump = 40 gallons/min

We need to find find the number of gallons of water removed from the basement.

Solution:

Now Given:

After half an hour, the one pump burns out.

Now we know that;

1 hour = 60 mins

$\frac12$ hour = $\frac{60}{2}=30\ mins$

Now for 30 mins both the pumps were working and removing the water.

So we can say that;

Water remove for first 30 mins = $40\times2\times30=2400\ gallons$

Also Given:

the second pump finishes removing the water half an hour later.

So we can say that;

Water removed for next 30 mins = $40\times 30\times1 =1200\ gallons$

Now we can say that;

Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .

framing in equation form we get;

Total water removed from the basement = $2400+1200=3600\ gallons.$

Hence 3600 gallons of water was removed from the basement.

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3 years ago