Answer:
The theorem here is essentially that
if a and 3 are disjoint sets with
exactly one element each, then their
union has exactly two elements. ...
Peano shows that it's not hard to
produce a useful set of axioms that
can prove 1+1=2 much more easily
than Whitehead and Russell do.
What needs to be done first is to add up females and males that have passed.
42 + 14 = 56
so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75
out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
NOW WE ARE DOING FAILS.
15 + 5 = 20
so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75
out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25
check work; 0.75 + 0.25 = 1.00
i hope this helped! :)
Breads/cereals;
11 * 140 = 1540 calories
Fruits/vegetables;
9 * 60 = 540 calories
Meat/milk;
x * 180 = 2800 - (1540 + 540)
180x = 2800 - 2080
180x = 720
x = 4 servings
In the given graph point B is a relative maximum with the coordinates (0, 2).
The given function is 
.
In the given graph, we need to find which point is a relative maximum.
<h3>What are relative maxima?</h3>
The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.
In the graph, the maximum point is (0, 2).
Therefore, in the given graph point B is a relative maximum with the coordinates (0, 2).
To learn more about the relative maximum visit:
brainly.com/question/2321623.
#SPJ1
We know that
if two lines are perpendicular
then
the slopes
m1*m2=-1
step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3
step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4
step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
AB is not perpendicular to CD
