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Alexus [3.1K]
3 years ago
8

A polynomial function has real coefficients, a leading coefficient of 1, and the zeros -6, 1, and 1. Write a polynomial function

of least degree in standard form.​
Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0

Answer:

{ \sf{ \underline{ {x}^{2} + 5x - 6 }}}

Step-by-step explanation:

(x + 6)(x - 1) \\  =  {x}^{2}  - x + 6x - 6 \\  =  {x}^{2}  + 5x - 6

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Slope: -1 intercept: -7.9
frosja888 [35]

Answer:

y = -x - 7.9

Step-by-step explanation:

Given:

m = -1

b = -7.9

y = mx + b

y = -x - 7.9

7 0
3 years ago
Read 2 more answers
-15x + 5 = -10x + 25 solve for x
tatuchka [14]

Answer:

Move all terms containing x to the left side of the equation.

−5x+5=25

Move all terms not containing x to the right side of the equation.

−5x=20

Divide each term by −5 and simplify.

x=−4

Step-by-step explanation:

6 0
3 years ago
The Ross family had 100 relatives at their big Thanksgiving dinner of all the guest nine he had French heritage 80 had English h
il63 [147K]
Hi, Deedee. I am quite confused with the numbers that you've given because they don't add up to 100. Nevertheless, if by 'this', you mean the Thanksgiving culture, then you would just count the English and the Native American heritage. This is because the first Thanksgiving dinner was shared between the English colonists and the Native American tribes.

I hope I was able to help you in a way. Have a good day.
8 0
3 years ago
What is and how do you do it?<br><br> H(x) = 4x-2<br> G(x) = x^2 -5<br><br> Find h(x) + g(x)
sineoko [7]

h(x)=4x-2\\\\(x)=x^2-5\\\\h(x)+g(x)=(4x-2)+(x^2-5)=x^2+4x+(-2-5)\\\\=x^2+4x-7

6 0
3 years ago
4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
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