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3 years ago

8

A polynomial function has real coefficients, a leading coefficient of 1, and the zeros -6, 1, and 1. Write a polynomial function

of least degree in standard form.

1 answer:

vaieri [72.5K]3 years ago

5 0

Answer:

${ \sf{ \underline{ {x}^{2} + 5x - 6 }}}$

Step-by-step explanation:

$(x + 6)(x - 1) \\ = {x}^{2} - x + 6x - 6 \\ = {x}^{2} + 5x - 6$

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3 years ago

Which number line shows the solution set for |p-3|=9?

Mademuasel [1]

Answer:

Option b

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Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function $f(x) = |x|$ x> 0 for all real numbers.

Then the equation:

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We solve the case (i)

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Then the solution is:

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