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Ivanshal [37]
3 years ago
7

Sarah measured her square garden to have an area of 122 ft​ 2​ . How long is one side of Sarah’s garden?

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

30.5 ft squared

Step-by-step explanation:

First, find the area and shape. If it is a square then you want to divide by four since all sides are equal. So divide 122 by 4 and you get the answer.

<h2><u><em>If you need more help or explanation, follow up in the comments below. :P</em></u></h2>
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olga_2 [115]
This would be 12 - 12*cos(30) = 12 - 6\sqrt{3} =  1.608 ft off the ground. 
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3 years ago
What is the surface area of the rectangular<br> prism shown by the net?
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Answer:

80

Step-by-step explanation:

There are four 4 by 3 rectangles, so I did 4x3 and got 12, then multiplied by 4 to get 48.  There are also two 4 by 4 squares, so 4x4=16 and 16x2=32

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Answer:

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3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
2 years ago
Anyone know the answer to this?
AlladinOne [14]

Answer:

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Step-by-step explanation:

3 0
2 years ago
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