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ioda
3 years ago
14

how many different four letter permutations can be formed using four letters out of the first 12 in the alphabet?

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

Permutations of four letters from a set of 12 letters. So

P_{(12,4)} = \frac{12!}{(12-4)!} = 11800

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

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The product of 13 and M plus the product of 2.7 8 in
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A company that makes pencils realized that 2 out of every 25 pencils were defective. How many pencils out of 200 will be defecti
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6 0
3 years ago
emma will roll two number cubes labeled 1 through 6. She will record the sum of the two numbers after each roll. She will roll t
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Answer:

75 times

Step-by-step explanation:

First of all let's ook at the 36 possible outcomes and their sums.

2=1,1

3=1,2 2,1

4=1,3 ; 2,2 ; 3,1

5=1,4 ; 2,3 ; 3,2 ; 4,1

6=1,5 ; 2,4 ; 3,3 ; 4,2 ; 5,1

7=1,6 ; 2,5 ; 3,4 ; 4,3 ; 5,2 ; 6,1

8=2,6 ; 3,5 ; 4,4 ; 5,3 ; 6,2

9=3,6 ; 4,5 ; 5,4 ; 6,3

10=4,6 ; 5,5 ; 6,4

11=5,6 ; 6,5

12=6,6

Looking at the above, there are 4 sums equal to 5 out of a total of 36 sums.

Thus, probability of getting a sum equal to 5 is;

P(5) = 5/36

Now,since the cubes are rolled 540 times, number of times a sum equal to 5 will appear will be;

(5/36) x 540 = 75 times

4 0
3 years ago
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S=weight of soybean protein, C=weight of cornmeal protein.
Total weight of each protein is 0.18S+0.19C=0.17×360=61.2 lb.
Total weight of meal is S+C=360 lb. So S=360-C.
Therefore 0.18(360-C)+0.19C=61.2, 64.8-0.18C+0.19C=61.2, 0.01C=-3.6.
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5 0
3 years ago
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