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AfilCa [17]
4 years ago
14

Determine the relationship between the lines that pass through the given points: line

Mathematics
1 answer:
Kisachek [45]4 years ago
4 0
A. (-3,5)(0,7)
    slope = (7 - 5) / (0 - (-3) = 2/3

y = mx + b
slope = 2/3
(0,7)...x = 0 and y = 7
sub and find b, the y int
7 = 2/3(0) + b
7 = b....this is ur y int (0,7)
so ur equation for this line is : y = 2/3x + 7

b. (6,2)(9,4)
    slope = (4 - 2) / (9 - 6) = 2/3

y = mx + b
slope(m) = 2/3
(6,2)...x = 6 and y = 2
sub and find b, the y int
2 = 2/3(6) + b
2 = 4 + b
2 - 4 = b
-2 = b...this is ur y int (0,-2)
so this equation is : y = 2/3x - 2

so " a " has a slope of 2/3 and a y int of 7 and " b " has a slope of 2/3 and a y int of -2.

ur lines are parallel lines.....parallel lines will have the same slope and different y intercepts <===

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Step-by-step explanation:

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A regular octagon has a radius of 6 ft and a side length of 4. 6 ft. A regular octagon has a radius of 6 feet and side lengths o
skad [1K]

The regular octagon has eight equal sides. Then the area of the regular octagon of side length be 4.6 is 102 ft².

<h3>What is a regular octagon?</h3>

It is a polygon that has eight equal sides. In a regular octagon, the opposite sides are parallel. And its diagonals are also equal and intersect at mid-point.

Given

A regular octagon has a radius of 6 ft and a side length of 4.6 ft.

We know the formula for the regular octagon.

Area of the regular octagon = 2(1 + \sqrt{2}) a²

Where a be the side of a regular octagon.

Then the area of the regular octagon will be.

\rm Area = 2 (1+\sqrt{2} ) a^2\\\\Area = 2*(1 + 1.414) *4.6^2\\\\Area = 2 * (2.414)* 21.16\\\\Area = 102.16

Thus, the area of the regular octagon of side length be 4.6 is 102 ft².

More about the regular octagon link is given below.

brainly.com/question/858868

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Step-by-step explanation:

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