Question

Can you solve this????? Super hard!

Answer 1

Answer:

  $\textbf{J. }\dfrac{1}{x^2-x}$

Step-by-step explanation:

Factor the denominator and cancel the common factor.

  $\dfrac{x+1}{x^3-x}=\dfrac{x+1}{x(x^2-1)}=\dfrac{x+1}{x(x-1)(x+1)}=\dfrac{1}{x(x-1)}\\\\=\boxed{\dfrac{1}{x^2-x}}$