Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Step-by-step explanation:
Bing dad beans Finke little
Answer:
122+6-(122*3)= -238
-26+6-(3*-26)= 58
-25+6-(-25*3)= 56
12+6-(3*12)= -8
46+6-(3*46)= -86
Step-by-step explanation:
Answer:
c 0.269
Step-by-step explanation:
2x3=6 2x6=18 3x6=24 so its non repeating here i bless the eyes
