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siniylev [52]
3 years ago
10

The length of a rectangle is 2 units shorter than two-thirds of the width, w. Which of the following expressions represent the p

erimeter of the rectangle.
A
(10/3)w - 1

B
(4/3)w + 1

C
2w - 2

D
(8/3)w - 2

E
2w - 1
Mathematics
1 answer:
sasho [114]3 years ago
5 0
B. (4/3)w + 1, just take it step by step
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Jeanette can walk 1 km in 11 minutes. At the same rate, how far can she walk in 55 minutes?
gladu [14]
11 minutes = 1 km

11 x 5 = 55 minutes
1 x 5 = 5 km.

She can walk 5 km in 55 minutes.
3 0
4 years ago
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Which of these debts could possibly be forgiven under Chapter 7 bankruptcy? A. Credit Card Debt B. Child Support C. Alimony D. A
a_sh-v [17]
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4 0
4 years ago
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PLS HELP I DONT UNDERSTAND :( WILL GIVE BRAINLIEST !!!
vodomira [7]

the answer is c

i already done it

5 0
4 years ago
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David's gasoline station offers 4 cents off per gallon if the customer pays in cash and does not use a credit card. Past evidenc
shusha [124]

Answer:

0.6535

Step-by-step explanation:

Given that during a one-hour period twenty-five customers buy gasoline at this station.

Let X be the no of persons out of these 25 who pay by cash.

X has two outcomes and each trial is independent of other.

Hence X is binomial (n=25, p=0.40)

Required probability

= P(X\geq 10)\\=P(10)+P(11)+...+P(25)\\=\Sigma_{10}^{25}  25Cr (0.4)^r (1-0.4)^{25-r}

=0.6535

7 0
3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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