Answer:
(-1, 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-2x - y = 0
10x + y = -8
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Combine equations: 8x = -8
- Isolate <em>x</em>: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: -2x - y = 0
- Substitute in <em>x</em>: -2(-1) - y = 0
- Multiply: 2 - y = 0
- Isolate <em>y</em> term: -y = -2
- Isolate <em>y</em>: y = 2
Answer:
u = -132
Step-by-step explanation:
33=-u/4
33*4=-u
132=-u
132/-1=u
-132=u
u = -132
Check:
33= -1(-132)/4
33=132/4
33=33
Hope this helps. Have a nice day.
6b^5-3b^4-35b^3-10b^2+43b+63
Answer:
Step-by-step explanation:
Find the area of the base
The base is a square.
The formula is Area = s^2
s = 1.5
Area = 1.5^2
Area = 2.25 sq cm.
Area of 1 triangle
h = 2.4
b = 1.5
Area = 1/2 * b * h
Area = 1/2 * 1.5 * 2.4
Area = 1.8 cm^2
Area of 4 triangles
Area = 4 * area of 1 triangle
Area = 4 * 1.8
Area = 7.2
Total Area = 2.25 + 7.2 = 9.45 cm^2
