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kykrilka [37]
2 years ago
15

What has 2 dimensional shape and the perimeter is also known as a circumference

Mathematics
1 answer:
Keith_Richards [23]2 years ago
4 0
A circle
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If a = 5^x, b = 5^y and a^y×b^x = 25 then prove that: xy =1​
avanturin [10]

a =  {5}^{x}  \\ b =  {5}^{y}  \\  {a}^{y}  \times  {b}^{y}  = 25 \\ prove \: ( {5}^{x} )^{y}  \times ( {5}^{y} ) ^{x}  = 25 \\  {5}^{xy}  \times  {5}^{yx}  = {5}^{2} \\  {5 }^{xy + yx}  = 5^{2}  \\ 5^{2xy}  =  {5}^{2} \\ is \:  \: 2xy = 2 \\ xy =  \frac{2}{2}  \\ xy = 1

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3 years ago
6338 divided by 43 with remainder
Paladinen [302]

Answer:

147 r17

Step-by-step explanation:

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9. Leonard made a deposit of $4,500 into a
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id say a

Step-by-step explanation:

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3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
2 years ago
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