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Ilia_Sergeevich [38]
3 years ago
12

How many electrons are in an atom of chlorine with a -1 charge? 17 16 18 8

Chemistry
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

18

Explanation:

The atomic number of chlorine is 17 therefore the atom has 17 electrons, the ion however has 1 extra electron. The charge becomes negative because electrons have a negative charge. 17 + 1 = 18, therefore a chlorine ion with a charge of -1 has 18 electrons.

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Which reaction would cause an increase in entropy? A. SO2Cl2(g) SO2(g) + Cl2(g) B. PCl3(g) + Cl2(g) PCl5(g) C. 2CO(g) + O2(g) 2C
IrinaVladis [17]
A. SO2Cl2(g) --> SO2(g) + Cl2(g) 
<span>1 mole of SOCl2 becomes 1 mole SO2 and 1 mole Cl2 </span>
<span>1 mole --> 2 moles </span>
<span>entropy increases </span>

8 0
4 years ago
Read 2 more answers
My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h
Fed [463]

Answer:

P=atm

b=\frac{L}{mol}

Explanation:

The problem give you the Van Der Waals equation:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

First we are going to solve for P:

(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}

P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}

Then you should know all the units of each term of the equation, that is:

P=atm

n=mol

R=\frac{L.atm}{mol.K}

a=atm\frac{L^{2}}{mol^{2}}

b=\frac{L}{mol}

T=K

V=L

where atm=atmosphere, L=litters, K=kelvin

Now, you should replace the units in the equation for each value:

P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}

Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:

P=\frac{L.atm}{L-L}-atm

Then operate the fraction subtraction:

P=P=\frac{L.atm-L.atm}{L}

P=\frac{L.atm}{L}

And finally you can find the answer:

P=atm

Now solving for b:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}

Replacing units:

b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}

Multiplying and dividing units,(please see the second photo below), we have:

b=\frac{L-\frac{L.atm}{atm}}{mol}

b=\frac{L-L}{mol}

b=\frac{L}{mol}

7 0
3 years ago
Help please need help need help need help for chemistry
Varvara68 [4.7K]
If you type in the letters (uppercase and lowercase matters) into google it will give you the answers
8 0
3 years ago
What scientific instrument is sensitive enough to detect a planet transiting a star?
Stolb23 [73]
The correct scientific instrument is telescope.
5 0
3 years ago
Which group of extremophiles does thermus aquaticus belong to
Elan Coil [88]

Answer:

The correct answer is thermophiles.

Explanation:

Thermus aquaticus are heat resistant bacteria because these bacteria can survive under adverse environmental conditions like high temperature.

These bacteria belong to one of the most heat-loving groups of extremophiles that are thermophiles. Thermophiles are present in volcanic soil, geysers and around deep-sea vents where the temperature is extremely high.

Thermus aquaticus bacteria is used to manufacture an enzyme called Taq DNA polymerase, which is heat resistant and also an important factor in molecular biology.

7 0
4 years ago
Read 2 more answers
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