41.38 % Mg
55.17 % O
3.45 % H
Explanation:
What is the percent composition of magnesium hydroxide Mg(OH)₂?
To find the percent composition we follow the next algorithm.
First we calculate the molar mass of Mg(OH)₂:
molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2
molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole
Now we devise the next reasoning:
if in 58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H
then in 100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H
X = (100 × 24) / 58 = 41.38 % Mg
X = (100 × 32) / 58 = 55.17 % O
X = (100 × 2) / 58 = 3.45 % H
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percent composition
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Answer:
= -4.2°C
= 49.4°C
Explanation:
A Carnot cycle is known as an ideal cycle in thermodynamic. Therefore, in theory, we have:
|
| = 
Similarly,
|
| = |
| + |
|
During winter, the value of |
| = 20°C = 273.15 + 20 = 293.15 K and |
| = 1.5 kW. Therefore,
|
| = 0.75(
-
)
Similarly,
|
| = 1 - 
1.5/0.75*(293.15-
) = 1 - (
/293.15
Further simplification,
= -4.2°C
During summer,
= 25°C = 273.15+25 = 298.15 K, and |
| = 1.5 kW. Therefore,
|
| = 0.75(
-
)
Similarly,
|
| =
- 1
1.5/0.75*(
- 298.15) = (
/298.15
Further simplification,
= 49.4°C
A C and D are all correct, Helium and Hydrogen only have a 1s orbital, and helium has 2 protons, while hydrogen has 1, and finally Hydrogen has no neutrons while helium has 2. Helium does not however have 8 valence electrons as the 1s orbital can only hold 2, meaning B is the “correct” (false) answer.
Answer:
d
Explanation:
the farther you are from the equater the dolder it is.