All categories

2 years ago

What is the value of the underlined digit 24 the 2 is underlined?

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

3 0

Answer:

Step-by-step explanation:

ones= 1

tens= 10

Hundreds= 100

The difference between ones and tens is the 0. ones=1. tens=10

24

The 2 is in the beginning so its the 10's place. The 4 is the second number so its in the ones place

You might be interested in

15. What is the algebraic notation of a figure is Translated 8 units left and 2 units up?

sasho [114]

Answer:

Please check the explanation.

Step-by-step explanation:

When a figure is translated with 8 units left and 2 units up, it means the translated figure can be obtained by subtracting 8 units from the x-axis and adding 2 units to the y-axis.

For example, if a point P(0, 0) is translated with 8 units left and 2 units up, the new position of the point will be:

(x, y) → (x-8, y+2)

P(0, 0) → P'(0-8, 0+2) = P'(-8, 2)

Thus, the new location of the image of point P will be: P'(-8, 2)

Therefore, option (a) is the correction answer.

FOR QUESTION 16

As the algebraic notation of a figure is Translated 2 units right and 5 units up.

Translating 'a' units right mean, we need to add 'a' units to the x-axis.

Thus, the rule will be:

(x, y) → (x+2, y+5)

Therefore, option (b) is correct.

4 0

2 years ago

Micah was asked to add the following expressions: 3x2−x−9x2+3x+2+−2x2+2x+5x2+3x+2 First, he combined like terms in the numerator

shtirl [24]

Micah was asked to add the following expressions:

$\frac{3x^2-x-9}{x^2+3x+2} + \frac{-2x^2+2x+5}{x^2+3x+2}$

First, he combined like terms in the numerator and kept the common denominator

First step is correct. He added the like terms in the numerator, because the denominators are same.

$3x^2 -x -9 -2x^2+2x+5becomes x^2 +x -4$

So he got , $\frac{x^2+x-4}{x^2+3x+2}$

In the next step, he cannot cancel out x^2 from the top and bottom . Because x-4 and 3x+2 are added with x^2

If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.

So Micah added the expression incorrectly. Final answer is not correct.

5 0

2 years ago

What is f(g(x)) for x > 5?

mel-nik [20]

Answer:

$\large\boxed{B.\ 4x^2-41x+105}$

Step-by-step explanation:

$f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105$