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3 years ago

Write (8a^-3)^2/3 in a simplest form. a. a^2/4 b. 4a^2 c. 1/4a^2 d. none of these

1 answer:

3 0

$(8a^{-3})^\frac{2}{3}=(8 \cdot \frac{1}{a^3})^\frac{2}{3}=(\frac{8}{a^3})^\frac{2}{3}=\sqrt[3]{(\frac{8}{a^3})^2}=\sqrt[3]{\frac{64}{a^6}}=\frac{\sqrt[3]{64}}{\sqrt[3]{a^6}}=\frac{4}{a^2}$

It doesn't equal any of the answers A, B, C.
The answer is D.

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A clinical psychologist wants to test whether experiencing childhood trauma reduces one's self-efficacy in adulthood. He randoml

lidiya [134]

Answer:

No, there is not any sufficient evidence to conclude that individuals who have experienced childhood trauma have lower self-efficacy in adulthood.

Step-by-step explanation:

We are given that a clinical psychologist wants to test whether experiencing childhood trauma reduces one's self-efficacy in adulthood.

He randomly selects 22 adults who have experienced childhood trauma and finds that their mean self-efficacy score equals 118.1.

Self-efficacy scores in the general population of adults are distributed normally with a mean equal to 118.5 and a standard deviation equal to 18.8 .

Let $\mu$ = mean self-efficacy score.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 118.5 {means that the individuals who have experienced childhood trauma have higher or same self-efficacy in adulthood}

Alternate Hypothesis, $H_A$ : $\mu$ < 118.5 {means that the individuals who have experienced childhood trauma have lower self-efficacy in adulthood}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean self-efficacy score = 118.1

$\sigma$ = population standard deviation = 18.8

n = sample of adults who have experienced childhood trauma = 22

So, test statistics = $\frac{118.1-118.5}{\frac{18.8}{\sqrt{22} } }$

= -0.0998

The value of z test statistics is -0.0998.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical value of -1.645 for left-tailed test.

Since our test statistic is more than the critical value of z as -0.0998 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the individuals who have experienced childhood trauma have higher or same self-efficacy in adulthood.

4 0

4 years ago

Look at the picture . . . . .. . . . . . .

frozen [14]

Answer:

1 D

2 A

and

3rd will be B and C

if you want explanation you can comment

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3 years ago

Help needed ASAP will give brainliest and 5 STARS VOTE RATE

harkovskaia [24]

Answer:

Nebula

Step-by-step explanation:

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3 years ago

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How estimation helps you to place the decimal point when multiplying 3.9x5.3

myrzilka [38]

3.9 can be rounded to 4.
5.3 can be rounded to 5.

4 x 5 = 20

That tells you that 3.9 x 5.3 has a digit in the tens place.

Then you can proceed to multiply 39 and 53, which equals 2067.
(Note: I removed the decimals on purpose)

Now we know that in 2067, the 2 should be in the tens place. That means 0 is in the ones place and that 6 is in the tenths place. That leaves 7 to be in the hundreths place.

Therefore, 3.9 x 5.3 = 20.67

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3 years ago

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Pls help I need it pls

Whitepunk [10]

Answer:

Step-by-step explanation:

First, in millimeters, so the first square is 2025, and the second square is 900. Add those to get 2925 mm. Then, look at the answers. Whichever one has 2925 mm squared first, then a smaller number, that's the one. Therefore, the answer is 2925 mm squared and 29.25 cm squared.

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3 years ago

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