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nexus9112 [7]
3 years ago
7

Write (8a^-3)^2/3 in a simplest form. a. a^2/4 b. 4a^2 c. 1/4a^2 d. none of these

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
3 0
(8a^{-3})^\frac{2}{3}=(8 \cdot \frac{1}{a^3})^\frac{2}{3}=(\frac{8}{a^3})^\frac{2}{3}=\sqrt[3]{(\frac{8}{a^3})^2}=\sqrt[3]{\frac{64}{a^6}}=\frac{\sqrt[3]{64}}{\sqrt[3]{a^6}}=\frac{4}{a^2}

It doesn't equal any of the answers A, B, C.
The answer is D.
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bearhunter [10]
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3 years ago
Use the distance formula distance, to find the distance to the nearest tenth , between each pair of points A(6,2) and D(-3,-2)
marusya05 [52]

Answer:

The distance between A and D to the nearest tenth is;

9.8\text{ units}

Explanation:

Given the two points;

A(6,2)\text{ and D(-3,-2)}

Applying the distance between two points formula;

d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

substituting the given coordinates we have;

\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}

Simplifying;

\begin{gathered} AD=9.8488578 \\ AD\approx9.8 \end{gathered}

Therefore, the distance between A and D to the nearest tenth is;

9.8\text{ units}

4 0
2 years ago
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