Write 9020000 in standard form?
1 answer:
You might be interested in
Answer:
P(x ≥ 30) = 0.3859
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
This probability is going to be 1 subtracted by the pvalue of Z when X = 30. So
has a pvalue of 0.6141
1 - 0.6141 = 0.3859
So
P(x ≥ 30) = 0.3859