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3 years ago

At a tailor shop, it costs $6.79 to

Mathematics

2 answers:

Margarita [4]3 years ago

7 0

Answer: $29.62

Step-by-step explanation:

6.79 * 3 = 20.37

9.25 * 1 = 9.25

So, 20.37 + 9.25 = 29.62

wlad13 [49]3 years ago

4 0

Answer:

Step-by-step explanation:

(6.79*3)+(9.25*1)=29.62

we multiply the cost of shortening a pair of pants by the number of pants brought and the cost of a dress multiplied by the number of dresses to get our answer

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I dont understand this equation.

amm1812

Where is the question and what is it?

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2 years ago

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Lenox ironed 1/4 of the shirts over the weekend. She plans to split the remainder of the work equally over the next 5 evenings.

MrMuchimi

3/20, or 0.15 of the shirts each evening

1 - 1/4 = 3/4

(3/4) / 5 = (3/4) / (5/1) = (3/4) x (1/5) = 3/20 = 0.15

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3 years ago

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The curve given by x=sin(t),y=sin(t+sin(t)) has two tangent lines at the point (x,y)=(0,0). List both of them in order of increa

SOVA2 [1]

Answer:

y = 0

y =2x

Step-by-step explanation:

Given parametric equations:

x (t) = sin (t)

y (t) = sin (t + sin (t))

The slope of the curve at any given point is given by dy / dx we will use chain rule to find dy / dx

(dy / dx) * (dx / dt) = (dy / dt)

(dy / dx) = (dy / dt) / (dx / dt)

Evaluate dx / dt and dy / dt

dx / dt = cos (t)

dy / dt = cos (t + sin (t)) * (1+cos (t))

Hence,

dy / dx = (1+cos(t))*cos(t + sin (t))) / cos (t)

@Given point (x,y) = 0 we evaluate t

0 = sin (t)

t = 0 , pi

Input two values of t and compute dy / dx

@ t = 0

dy / dx = (1 + cos (0))*cos (0 + sin (0))) / cos (0)

dy / dx = (1+1)*(1) / (1) = 2 @ t = 0

@t = pi

dy / dx = ( 1 + cos (pi))* cos (pi + sin (pi)) / cos (pi)

dy / dx = (1-1) * (-1) / (-1) = 0 @ t = pi

The corresponding gradients are 0 and 2 in increasing order and their respective equations are:

y = 2x

y = 0

5 0

2 years ago

Which phrase represents the algebraic expression 5x-9

Gre4nikov [31]

the product of five times a number and nine the difference of nine times a number and five the sum of five times a number and five the difference of five times a number and nine

6 0

3 years ago

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Please help me with this

denis23 [38]

Answer:

20) $\displaystyle [4, 1]$

19) $\displaystyle [-5, 1]$

18) $\displaystyle [3, 2]$

17) $\displaystyle [-2, 1]$

16) $\displaystyle [7, 6]$

15) $\displaystyle [-3, 2]$

14) $\displaystyle [-3, -2]$

13) $\displaystyle NO\:SOLUTION$

12) $\displaystyle [-4, -1]$

11) $\displaystyle [7, -2]$

Step-by-step explanation:

20) {−2x - y = −9

{5x - 2y = 18

⅖[5x - 2y = 18]

{−2x - y = −9

{2x - ⅘y = 7⅕ >> New Equation

__________

$\displaystyle \frac{-1\frac{4}{5}y}{-1\frac{4}{5}} = \frac{-1\frac{4}{5}}{-1\frac{4}{5}}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of 4]; $\displaystyle 4 = x$

_______________________________________________

19) {−5x - 8y = 17

{2x - 7y = −17

−⅞[−5x - 8y = 17]

{4⅜x + 7y = −14⅞ >> New Equation

{2x - 7y = −17

_____________

$\displaystyle \frac{6\frac{3}{8}x}{6\frac{3}{8}} = \frac{-31\frac{7}{8}}{6\frac{3}{8}}$

$\displaystyle x = -5$ [Plug this back into both equations above to get the y-coordinate of 1]; $\displaystyle 1 = y$

_______________________________________________

18) {−2x + 6y = 6

{−7x + 8y = −5

−¾[−7x + 8y = −5]

{−2x + 6y = 6

{5¼x - 6y = 3¾ >> New Equation

____________

$\displaystyle \frac{3\frac{1}{4}x}{3\frac{1}{4}} = \frac{9\frac{3}{4}}{3\frac{1}{4}}$

$\displaystyle x = 3$ [Plug this back into both equations above to get the y-coordinate of 2]; $\displaystyle 2 = y$

_______________________________________________

17) {−3x - 4y = 2

{3x + 3y = −3

__________

$\displaystyle \frac{-y}{-1} = \frac{-1}{-1}$

$\displaystyle y = 1$ [Plug this back into both equations above to get the x-coordinate of −2]; $\displaystyle -2 = x$

_______________________________________________

16) {2x + y = 20

{6x - 5y = 12

−⅓[6x - 5y = 12]

{2x + y = 20

{−2x + 1⅔y = −4 >> New Equation

____________

$\displaystyle \frac{2\frac{2}{3}y}{2\frac{2}{3}} = \frac{16}{2\frac{2}{3}}$

$\displaystyle y = 6$ [Plug this back into both equations above to get the x-coordinate of 7]; $\displaystyle 7 = x$

_______________________________________________

15) {6x + 6y = −6

{5x + y = −13

−⅚[6x + 6y = −6]

{−5x - 5y = 5 >> New Equation

{5x + y = −13

_________

$\displaystyle \frac{-4y}{-4} = \frac{-8}{-4}$

$\displaystyle y = 2$ [Plug this back into both equations above to get the x-coordinate of −3]; $\displaystyle -3 = x$

_______________________________________________

14) {−3x + 3y = 3

{−5x + y = 13

−⅓[−3x + 3y = 3]

{x - y = −1 >> New Equation

{−5x + y = 13

_________

$\displaystyle \frac{-4x}{-4} = \frac{12}{-4}$

$\displaystyle x = -3$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

_______________________________________________

13) {−3x + 3y = 4

{−x + y = 3

−⅓[−3x + 3y = 4]

{x - y = −1⅓ >> New Equation

{−x + y = 3

________

$\displaystyle 1\frac{2}{3} ≠ 0; NO\:SOLUTION$

_______________________________________________

12) {−3x - 8y = 20

{−5x + y = 19

⅛[−3x - 8y = 20]

{−⅜x - y = 2½ >> New Equation

{−5x + y = 19

__________

$\displaystyle \frac{-5\frac{3}{8}x}{-5\frac{3}{8}} = \frac{21\frac{1}{2}}{-5\frac{3}{8}}$

$\displaystyle x = -4$ [Plug this back into both equations above to get the y-coordinate of −1]; $\displaystyle -1 = y$

_______________________________________________

11) {x + 3y = 1

{−3x - 3y = −15

___________

$\displaystyle \frac{-2x}{-2} = \frac{-14}{-2}$

$\displaystyle x = 7$ [Plug this back into both equations above to get the y-coordinate of −2]; $\displaystyle -2 = y$

I am delighted to assist you anytime my friend!

7 0

3 years ago