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ikadub [295]
3 years ago
8

The distance between two places is 120 km. A car travelling at a certain speed can cover the distance in 2 hours 30 minutes. By

how many km/h should the speed of the car be increased for it to take 30 minutes less to cover the distance?
Don't spam!!
Step by step explanation is needed..​
Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

Distance between two places=120 km

Step-by-step explanation:

 

Time= 2 hrs 30 min

       =(2*60)min+30min

       =120min+30min

       =150min=150/60 hr

        = 5/2 hr

Speed = distance /time

          = (120/5/2)km/hr

          =(120×2/5)km/hr

          =(240/5)km/hr

          = 48 km/hr

New time = 2 hr 30min-30min

               = 2hr

Distance =120km

Speed  = Distance /time

           =120/2 km/hr

           = 60 km/hr

Increase in speed=(60-48)km/hr  

                            =12km/hr

Another way to show :

Distance = 120km

speed=Distance/time

=120/2.5=48 km/hr

New speed=120/2=60 Km/hr

change inspeed=60-48=12km/hr

-BARSIC- [3]3 years ago
5 0

Distance = 120 km

Time = 2hr 30min

speed = distance/ time

Average speed = 120/ 2.5 because 2h r30min = 2.5 hrs

120/2.5 = 48km/h

2hr30min - 30min = 2hrs

120/2 = 60km/h

=> (60–48)km/h = 12km/h

#Ojaswi's Fan

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The volume of a sphere is decreasing at a constant rate of 9988 cubic centimeters per minute. At the instant when the volume of
Inessa05 [86]

Using implicit differentiation, it is found that the rate of change of the surface area of the sphere -2201.293 square centimeters per second.

<h3>What is the volume of a sphere?</h3>
  • The volume of a sphere, of radius r, is given by:

V = \frac{4\pi r^3}{3}

<h3>What is the surface area of a sphere?</h3>
  • The surface area of a sphere, of radius r, is given by:

S = 4\pi r^2

<h3>What is the rate of change?</h3>

Applying <em>implicit differentiation</em>, the rate of change of both the volume and the surface area can be found, as follows:

\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}

\frac{dS}{dt} = 8\pi r\frac{dr}{dt}

Volume of 3131 cubic centimeters, hence:

V = \frac{4\pi r^3}{3}

\frac{4\pi r^3}{3} = 3131

4\pi r^3 = 3(3131)

r = \sqrt[3]{\frac{3(3131)}{4\pi}}

r = 9.0754

The volume of a sphere is decreasing at a constant rate of 9988 cubic centimeters per minute, hence:

\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}

-9988 = 4\pi (9.0754)^2\frac{dr}{dt}

\frac{dr}{dt} = -\frac{9988}{4\pi (9.0754)^2}

\frac{dr}{dt} = -9.651

Then, the <u>rate of change of the surface area</u> of the sphere is given by:

\frac{dS}{dt} = 8\pi (9.0754)(-9.651) = -2201.293

The rate of change of the surface area of the sphere -2201.293 square centimeters per second.

To learn more about implicit differentiation, you can take a look at brainly.com/question/25608353

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