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3 years ago

Please help me with this! I would appreciate it :)

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

1. b. Commutative Property of Addition
Reason: There is no multiplication used

2. a. 60
Reason: 36 + 24 = 60

3. b. 3d + 9
Reason: Simplification and combining like terms :)

4. b. 4,-1
Reason: Coefficients are the numbers in front of variables

5. b. 36m + 9
Reason: Just use distributive property (multiply 9 into both terms inside parenthesis)

6. b. 95.488
Reason: b = 165.288 - 39.7 - 30.1

7. The question is cut off, unanswerable

8. c. 5a, -3a
Reason: Like terms are things you can combine. So technically the answers could be b. and c. but just go with c. because they have variables.

9. b. 16
Reason: just add 4 to both sides to get the "a" by itself

Best of luck to you!

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What’s 100+100 I’ll make brainliest

eduard

Answer:its 200

Step-by-step explanation:

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3 years ago

Read 2 more answers

Possible values of x in 6x^2 + 432 = 0

Wewaii [24]

$6x^2 + 432 = 0 \\
x^2+72=0\\
x^2=-72\\
x=-\sqrt{-72} \vee x=\sqrt{-72}\\
x=-6\sqrt2 i \vee x=6\sqrt 2 i
$

3 0

4 years ago

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

The standard error is given by the following formula:

$SE=\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$

And replacing we have:

$SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

Part c: What is a 95% confidence interval estimate of the difference between the population mean ratings for the two sizes of ships?

Confidence interval

Now we have everything in order to replace into formula (1):

$3.92-1.96\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=2.009$

$3.92+1.96\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=5.830$

So on this case the 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

7 0

3 years ago

Wrtie the numbers in increasaing order, 4,-9,-5,9,-2,3

Lyrx [107]

Increasing order means from least to greatest.

-9 is the greatest negative number.

-5 is the 2nd negative greatest number.

-2 is the least negative number.

3 is the least positive number.

4 is the second greatest positive number.

9 is the greatest positive number.

So, the answer is: -9,-5,-2,3,4,9

Hope I helped!

6 0

3 years ago

Read 2 more answers

Max has 5 red cars 1/3 of the cars are red how many are left.

Pie

So 5 red cars
1/3 of all cars are red
therefor
5=1/3 of all cars
'of' means multply
5=1/3 times all cars
multiply both sides by 3
15=all cars

how many are left
basically how many are NOT red
15=all
red=5
all-red=others
15-5=others=10
10 cars are left

4 0

4 years ago