Answer:
7a. D)
7b. $78
Step-by-step explanation:
7a: We're given the information that there's a daily fee of $50 and $0.35 per mile driven, which is m. We can write "$0.35 per mile driven" as 0.35m. Then, the total amount of money it costs represented as an expression is 50 + 0.35m, thus, making it answer D).
7b: In this problem, we have to take our previous expression 50 + 0.35m, plug in the value of m, and simplify.
Thus, the answer is $78.
Have a lovely rest of your day/night, and good luck with your assignments! ♡
Step-by-step explanation:
If we let the width be w, then the length is w+3.5.
This means that w(w+3.5)=11
w^2 + 3.5w - 11 = 0
2w^2 + 7w - 22 = 0 (multiply both sides by 2)
(2w+11)(w-2)=0
w = -11/2 or w = 2 (disregard w = -11/2 as distance is positive)
This means that w=2, and thus the length is 2+3.5=5.5
Answer:
um
Step-by-step explanation:
um sorry bud cant help
Answer:
LCM of 9 and 15 is 45.
Step-by-step explanation:
What is the LCM of 9 and 15?
Find the prime factorization of 9.
Find the prime factorization of 15. 15 = 3 × 5.
Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 3 × 3 × 5.
LCM = 45.
(hope this helps can i plz have brainlist :D hehe)
Answer: 3.61×10^5 A
Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.
The formulae is given below as
B = u×Ia²/2(x²+a²)^3/2
Where B = strength of magnetic field on the axis of a circular loop = 4.15T
u = permeability of free space = 1.256×10^-6 mkg/s²A²
I = current on loop =?
a = radius of loop.
Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m
x = distance of the sensor away from center of loop = 2.10 cm = 0.021m
By substituting the parameters into the formulae, we have that
4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2
4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2
4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)
4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I
I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9
I = 4.80×10^-4 / 1.32665 ×10^-9
I = 3.61×10^5 A
