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3 years ago

I will pick the brainiest! Thanks :)

Mathematics

2 answers:

zavuch27 [327]3 years ago

8 0

Answer:

5+4.5=9.5

Step-by-step explanation:

Fynjy0 [20]3 years ago

6 0

Answer: the answer is in the attached file/picture ;)

Step-by-step explanation:

You might be interested in

(X^2+x-6)(2x^2+4x) factor completely

MissTica

Answer:

$2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring $x^2+x-6$ .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For $ax^2+bx+c$ we need to find u, v > $u\cdot \:v=a\cdot \:c$ and $u+v=b$ which we will group into $\left(ax^2+ux\right)+\left(vx+c\right)$ .

The values we have are... $a=1,\:b=1,\:c=-6$ and $u\cdot v=-6,\:u+v=1$ .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

$\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow \mathrm{True}$

$\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow \mathrm{False}$

Therefore $u=3,\:v=-2$ .

Now we want to $\mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right)$ . Which is $\left(x^2-2x\right)+\left(3x-6\right)$ .

Now we must factor x from $x^2-2x$ .

Lets apply the exponent rule of $a^{b+c}=a^ba^c$ which means $x^2=xx$ .

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of $3x-6$ .

Rewrite 6 as 3 * 2. $3x-3\cdot \:2$ .

Now factor out the common term of 3 > $3\left(x-2\right)$ .

$x\left(x-2\right)+3\left(x-2\right)$ > Factor out the common term of x - 2 > $\left(x-2\right)\left(x+3\right)$ .

Now lets factor $2x^2+4x$ .

Apply the previous exponent rule of $a^{b+c}=a^ba^c$ > $x^2=xx$ > $2xx+4x$ .

Now rewrite 4 as 2 * 2 > $2xx+2\cdot \:2x$ .

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get $2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$ .

Hope this helps!

7 0

3 years ago

PLZZZZZZZZ HELP!!! AHHHHH

Alex

When you dilate the image by 3, you would multiply each value by 3. Since it's center is around 0, we really don't have to worry about much else.

-1*3= -3

-2*3= -6

0*3= 0

The new set of points are (-3,-6,0)

I hope this helps!
~cupcake

6 0

3 years ago

Which equation is correct for XYT(sines and cosines)

vredina [299]

Since the equations are not shown, I believe that it could possibly be cos T = 4/17

5 0

3 years ago

Read 2 more answers

If the area of the vegetable garden is 170 square feet, which equation could be use to find the length of the tomato patch?

Tanzania [10]

Answer:

42.5 feet long.

Step-by-step explanation:

Assuming the shape of the garden is a sqaure, than

170/4=42.5 feet long.

5 0

3 years ago

Kellie currently has an average of 75 in her English class. If her grade is the mean of all her assignments, what would a grade

andriy [413]

Answer:

I just summited it, it was "Her mean grade would go up".

Step-by-step explanation:

8 0

3 years ago