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3 years ago

Calculate the slope for the following. Leave answer as a fraction. Show your work!

Mathematics

1 answer:

natali 33 [55]3 years ago

6 0

5+6=11
11+6=17
17+6=23
x=6

2+4=6
6+4=10
10+4=14
y=4

6÷4= 1.5
1.5 as a fraction is 3/2

ANSWER= 3/2

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An isosceles triangle has an angle that measures 68°. Which could be the measure of another angle in the triangle? A. 22° B. 56°

Lisa [10]

Answer:

Step-by-step explanation: 68+x+x=180. subtract 68 from both sides, and simplify the x's. so 2x=112. than divide by 2. x=56

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4 years ago

PLEASE ANSWER AS SOON AS POSSIBLE WILL GIVE "Brainliest" TO THE FIRST CORRECT PERSON!!!

saw5 [17]

Answer: $x=18$ ; $y=6\sqrt{3}$

Step-by-step explanation:

You can write two expressions that are in terms of 'x' and 'y'. This is a right triangle, so Pythagorean's theorem can be used. We can also use the angle to find the sine of 30 degrees.

Pythagorean's Theorem:

The values 'a' and 'b' are the two shorter sides of the triangle, while the value 'c' is the longest side of the triangle; the hypotenuse.

$a^2+b^2=c^2$

$x^2+y^2=(12\sqrt{3} )^2$

$x^2+y^2=12^2*\sqrt{3} ^2=432$

Sine of the Angle:

Sine is defined to be the opposite side divided by the hypotenuse. Let's take the sine of 30 degrees:

$sin(\alpha )=opposite/hypotenuse$

$sin(30)=y/12\sqrt{3}$

$\frac{1}{2} =y/12\sqrt{3}$

$y=6\sqrt{3}$

Plug this value of 'y' into the first expression derived from Pythagorean's theorem:

$x^2+y^2=432$

$x^2+(6\sqrt{3} )^2=432$

$x^2+108=432$

$x^2=432-108=324$

$x=\sqrt{324}$

$x=18$

Use this value of 'x' to solve for 'y' in the expression from Pythagorean's theorem:

$(\sqrt{324})^2+y^2=432$

$324+y^2=432$

$y^2=432-324=108$

$y=\sqrt{108}$

$y=\sqrt{36*3}$

$y=6\sqrt{3}$

7 0

2 years ago

Given the height, h, and the volume v of a certain cylinder, alex uses the formula v ph r 5 !§ to compute its radius, r, to be 1

dmitriy555 [2]

We know that
volume of a cylinder=pi*r²*h
r=√[V/(pi*h)]
r=10 m

A second cylinder has
V2=V-----> volume of the second cylinder
h2=25*h----> height of the second cylinder
r2----> radius of the second cylinder
r2=√[V2/(pi*h2)]----> r2=√[V/(pi*25*h)]---> r2=(1/5)*√[V/(pi*h)

r2=(1/5)*10-----> r2=2 m

the answer is
the radius of the second cylinder is 2 m

7 0

3 years ago

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larisa [96]

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