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3 years ago

Multiply and simplify : (4x -3)(-2x+1)

Mathematics

1 answer:

8_murik_8 [283]3 years ago

6 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ - 8 {x}^{2} + 10x - 3}}}}}$

Option B is correct.

Step-by-step explanation:

$\sf{(4x - 3)( - 2x + 1)}$

Use the distributive property to multiply each term of the first binomial by each term of the second binomial

$\dashrightarrow{ \sf{4x( - 2x + 1) - 3( - 2x + 1)}}$

$\dashrightarrow{ \sf{ - 8 {x}^{2} + 4x + 6x - 3}}$

Add like terms: 4x and 6x

$\dashrightarrow{ \sf{ - 8 {x}^{2} + 10x - 3}}$

Hope I helped!

Best regards! :D

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1.73639 rounded to the nearest thousanth

Maurinko [17]

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3 years ago

Barney has 14 dimes and quarters worth $2.15. write the system of equations

grigory [225]

Answer: 14 dimes and 3 quarters

Step-by-step explanation:

14x10=140+25=165+25=190+25=215 aka $2.15 meaning that there is 14 dimes and 3 quarters

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3 years ago

Find the average rate of change of the function f(x)=(3/-3x-5), on the interval x ∈ [0,3]

Svet_ta [14]

Answer:

The average rate of change on the given interval is 9/70

Step-by-step explanation:

Here, we are to find the average rate of change of the function on the given interval

We proceed as follows;

on an interval [a,b] , we can find the average rate of change using the formula;

f(b) - f(a)/b-a

From the question;

a = 0

b = 3

f(0) = -3/5

f(3) = -3/14

Substituting the values, we have;

-3/14-(-3/5)/3-0

= 3/5-3/14/3

= (42-15)/70/3

= 27/70/3

= 27/70 * 1/3 = 9/70

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2 years ago

The volleyball team and the wrestling team at Stamford High School are having a joint car wash today,

Sedbober [7]

Answer:

Money raised by each team = 94 + 11 = $105

Number of cars washed = 11

Step-by-step explanation:

Money already present with volleyball team = $50

Money raised by washing each car by volleyball team = $5

Let the number of cars washed = $x$

Money raised by washing cars = $5 $x$

Money already present with volleyball team = $94

Money raised by washing each car by volleyball team = $1

Money raised by washing cars = $1 $x$ = $ $x$

Given that, both the teams have raised same amount of money:

$50+5x=94+x\\\Rightarrow 44=4x\\\Rightarrow x=11$

Money raised by each team = 94 + 11 = $105

Number of cars washed = 11

4 0

3 years ago

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

$\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]$

The left and right endpoints of the $i$ -th subinterval, respectively, are

$\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8$

$r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8$

for $1\le i\le4$ , and the respective midpoints are

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8$

Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

$T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}$

Midpoint rule

We approximate the area for each subinterval by

$M_i=f(m_i)(\ell_i-r_i)$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}$

Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial $p_i(x)$ , where

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It so happens that the integral of $p_i(x)$ reduces nicely to the form you're probably more familiar with,

$S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))$

Then the integral is approximately

$\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}$

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0

3 years ago

Multiply and simplify : (4x -3)(-2x+1)​

Multiply and simplify : (4x -3)(-2x+1)