A circle has a diameter with endpoint at 5 + 18i and -3 + 2i. What is the center of the circle?
2 answers:
Answer:
center of the circle is 1+10i
Step-by-step explanation:
The end points of the diameter are 5 + 18i and -3 + 2i.
We know that the center of the circle is the mid point of the diameter.
Thus, in order to find the center of the circle we find the mid point of the diameter.
The mid point of the diameter with endpoints 5 + 18i and -3 + 2i is given by
Thus, the center of the circle is 1+10i
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For this type of problem, it is best to use Venn diagrams as shown in the picture. The areas where the circles intersect are the mutual events that occur together. The area where all circles intersect is denoted as x. These are the students who play all sports. Assuming all of the students play sports in the school, all of the numbers in the circles should add up to 405. The remaining area would be the difference. The solution is as follows:
Students who play tennis and hockey: 45 - x
Students who play hockey and softball: 60 - x
Students who play only tennis and softball: 39 - x
Students who only play tennis:
251 - 45 + x - 39 +x -x = x + 167
Students who only play hockey:
157 - x - 45 + x - 60 + x = x + 52
Students who only play softball:
111 - x - 60 + x - 39 + x = x + 12
The sum of all of these should be 405:
45-x+60-x+39-x+x+167+x+52+x+12 = 405
Solving for x,
x = 30
Therefore, there are 30 pupils who play all sports; 15 pupils who play tennis and hockey; 30 pupils who play hockey and softball; 9 pupils who play tennis and softball; 197 pupil who only play tennis; 82 pupils who only play hockey; and 42 pupils who only play softball.
Students who play tennis and hockey: 45 - x
Students who play hockey and softball: 60 - x
Students who play only tennis and softball: 39 - x
Students who only play tennis:
251 - 45 + x - 39 +x -x = x + 167
Students who only play hockey:
157 - x - 45 + x - 60 + x = x + 52
Students who only play softball:
111 - x - 60 + x - 39 + x = x + 12
The sum of all of these should be 405:
45-x+60-x+39-x+x+167+x+52+x+12 = 405
Solving for x,
x = 30
Therefore, there are 30 pupils who play all sports; 15 pupils who play tennis and hockey; 30 pupils who play hockey and softball; 9 pupils who play tennis and softball; 197 pupil who only play tennis; 82 pupils who only play hockey; and 42 pupils who only play softball.