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WARRIOR [948]
3 years ago
15

What is the fact family for the numbers 15, 5, and 3

Mathematics
1 answer:
Delvig [45]3 years ago
5 0
5×3=15
3×5=15
15÷5=3
15÷3=5
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The probability of rolling one die and getting any digit is \frac{1}{6}. That is because the desired outcome is only 1 digit out of the 6 total digits on each of the six sides.

That means the probability of rolling either a 1, a 2, or a 4 <em>if you are looking for any of those numbers specifically, </em>is \frac{1}{6}. But! You are looking to roll a 1, a 2, or a 4, without any preference among those three. Therefore, you are going to add the desired outcomes.

\frac{1}{6} + \frac{1}{6}  + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} = 0.5 = 50%

Above, are added the probability of rolling a 1 PLUS the probability of rolling a 2 PLUS the probability of rolling a 4, yielding a 50% probability.

Think about it. There are six total digits on a die. You are okay with rolling three of those. Three is half of six. Therefore, the probability of rolling the number you'd like is one-half, fifty-percent.

Likewise, since the probability of all complement events happening is 1 (or 100%), The odds against rolling either 1, 2, or 4 is also fifty-percent. 100% (which is rolling <em>any </em>number on a die) MINUS 50% (which is rolling a 1, a 2, or a 4 with no preference) EQUALS TO 50% (which is rolling a 3, a 5, or a 6).

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