Answer:
10,000
Step-by-step explanation:
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
6x^2-x-2 this is of the form ax^2+bx+c
jk=ac=-12 and j+k=b=-1 so j and k must be -4 and 3 so
6x^2+3x-4x-2
3x(2x+1)-2(2x+1)
(3x-2)(2x+1)
Answer:
<h2>it's simple<u>i</u><u>j</u><u>e</u><u>j</u><u>o</u><u>o</u><u>e</u><u>j</u><u>e</u><u>j</u><u>j</u><u>e</u><u>j</u><u>e</u><u>k</u><u>e</u></h2>
18 people x 18 walls = 324 minutes