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3 years ago

Which real number is not both a whole number and an integer? A. 18 B. 43 C. 0 D. −229

Mathematics

1 answer:

Verdich [7]3 years ago

5 0

A negative number is not considered a whole number...so ur answer is -229

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What is the absolute value of -3 1/2?

Lana71 [14]

Answer:

The absolute value of -3 1/2 is 3 1/2.

Step-by-step explanation:

The absolute value of a number is its distance from 0.

In this case the absolute value of -3 1/2 is 3 1/2.

Another way to write is I-3 1/2I

Using the absolute value bar

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3 years ago

The function c(x) = 72 ⋅ (1.04)x models the cost in dollars, c, of 1 ounce of a certain chemical used in a laboratory. x represe

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Check all cost is 92a +291a

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3 years ago

7. There are 12 singers auditioning for the school musical. In how many ways can the director choose first a lead singer and the

Finger [1]

Answer: The director can choose first a lead singer and then a stand-in for the lead singer in 132 ways.

Step-by-step explanation:

Given : The total number of singers auditioning for the school musical.= 12

The director wanted choose first a lead singer and then a stand-in for the lead singer.

We use Permutations here because order of selecting the singers matters.

The number of permutations of selecting r things out of n things = $^nP_r=\dfrac{n!}{(n-r)!}$

Similarly , the number of ways to select 2 singers in an order from 12 singers

$^{12}P_{2}{=\dfrac{12!}{(12-2)!}$

$=\dfrac{12\times11\times10!}{10!}=132$

Hence, the director can choose first a lead singer and then a stand-in for the lead singer in 132 ways.

8 0

3 years ago

Consider f (x) = StartRoot x squared minus 1 EndRoot and g (x) = StartRoot x squared + 1 EndRoot. What value(s) of x would make

dalvyx [7]

Answer:

Any value of x

Step-by-step explanation:

Given

$f(x) = \sqrt{x^2 - 1}$

$g(x) = \sqrt{x^2 + 1}$

Required

What value of x is $f(g(x)) = g(f(x))$

Solving for f(g(x))

$f(x) = \sqrt{x^2 - 1}$

$f(g(x)) = \sqrt{(\sqrt{x^2 + 1})^2 - 1}$

Solve the inner square

$f(g(x)) = \sqrt{(x^2 + 1 - 1}$

$f(g(x)) = \sqrt{x^2 } }$

$f(g(x)) = x$

Solving g(f(x))

$g(x) = \sqrt{x^2 + 1}$

$g(f(x)) = \sqrt{(\sqrt{x^2 - 1})^2 + 1}$

$g(f(x)) = \sqrt{x^2 - 1 + 1}$

$g(f(x)) = \sqrt{x^2 }$

$g(f(x)) = x$

Equate f(g(x)) and g(f(x))

$f(g(x)) = g(f(x))$

$x = x$

This implies that $f(g(x)) = g(f(x))$ at any value of x

8 0

3 years ago

The radius of circle C is 7 cm. ∠BCA (the non shaded region) has a measure of 1.36 radians. Find the length of arc BEA. Show you

Lelechka [254]

Answer: 9.52cm

Step-by-step explanation:

The data we have is:

Radius = 7cm

Angle of the arc = 1.36 rads

Now, the perimeter of a full circle is equal to:

P = 2*pi*r

Where 2*pi = 6.28 rads

Then the length of an arc of angle A is

P = A*r

then in our case:

P = 1.36*7cm = 9.52cm

7 0

3 years ago