2000 nibbles I think correct me if I’m wrong
Answer:
Option d) B is 1.33 times faster than A
Given:
Clock time, 

No. of cycles per instructions, 

Solution:
Let I be the no. of instructions for the program.
CPU clock cycle,
= 2.0 I
CPU clock cycle,
= 1.0 I
Now,
CPU time for each can be calculated as:
CPU time, T = 


Thus B is faster than A
Now,


Performance of B is 1.33 times that of A
Answer: squared ← number * number
Explanation: