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Vlad [161]
3 years ago
9

Find the volume ! Thanks

Mathematics
2 answers:
Shalnov [3]3 years ago
5 0

Answer:

Volume of cuboid = length × width × height

length = 20cm

width = 8cm

height = 15cm

Volume = 20cm × 8cm × 15cm

= 2400cm³

Volume of the cuboid is 2400cm²

Hope this helps.

Viefleur [7K]3 years ago
5 0

Answer:

2,400cm³

Step-by-step explanation:

FORMULA FOR VOLUME OF A CUBOID= L×B×H

WHERE L IS LENGTH = 20cm

B IS BREADTH = 15cm

H IS HEIGHT=8cm

:• VOLUME= 20cm ×15cm × 8cm

= 2,400cm³

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A group of 83 students are visiting the National Aquarium in Baltimore. Volunteers lead tours for groups no larger than 5 studen
Fiesta28 [93]

Answer:

17 tour guides

Step-by-step explanation:

First, we need to divide 83 by 5.

  • 83 ÷ 5 = 16 R 3

As you can see, there are 16 tour guides that can handle 5 students each. However, there are a remainder of 3 students, so we need one extra tour guide. Thus, the answer is 17 tour guides.

8 0
2 years ago
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Write the equation in slope-intercept form. y = 6(x + 2) + 5x
sveticcg [70]

Answer:

y=11x+12

Step-by-step explanation:

y = 6(x + 2) + 5x

y=6x+12+5x

y=11x+12

in slope interception form=  y=mx+c

                                                y=11x+12

5 0
2 years ago
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A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
A large company made $6,439,583 last year . what in the value of the 9 in $6,439,583?
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To the nearest degree what is the measure of each exterior angle of a regular dodecagon
malfutka [58]

Answer:

30^{\circ}

Step-by-step explanation:

We are asked to find the measure of each exterior angle of a regular dodecagon.

We know that a regular dodecagon is a 12 sided regular polygon with each side equal.

We know that measure of each angle of n-sided regular polygon can be found using formula:

\text{Each exterior angle}=\frac{360^{\circ}}{n}

Upon substituting n=12 in above formula, we will get:

\text{Each exterior angle of a regular dodecagon}=\frac{360^{\circ}}{12}

\text{Each exterior angle of a regular dodecagon}=30^{\circ}

Therefore, the measure of each exterior angle of a regular dodecagon is 30 degrees.

3 0
3 years ago
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