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Tom [10]
3 years ago
13

Find a number in the sequence 1) 100, 400, 610, ?, 652 2) 342, 128, ?, 26

Mathematics
1 answer:
dsp733 years ago
4 0

Answer:

1.  460

2.  216

Step-by-step explanation:

1.

From the series ,

100 , 400 , 610 , ? , 652

Writing the the digits in the revere order , i.e

001 , 004 , 016 , ? , 256

Now,

Now , getting the number in the form of the multiple of 4 as -

1  ,   1 * 4 = 4  ,   4 * 4 = 16 ,  ?  , 64 * 4 = 4  

Hence , the value for ?  =  16 * 4 =  64 .

Again , reversing 64 to get the missing number of the series -

460 .

Hence ,

The value for ? is 460 .

2.

From the series ,

342 , 128 , ? , 26

Now, multiplying the first digit with the second digit and merging it to the product of the second and third digit -

3 * 4 and  4 * 2 , 1 * 2 and 2 * 8 , ?

128 , 216 , ?

Hence ,

The value for question mark = 1 * 2 and  1 * 6 = 216

Hence ,

The value for ? is 216 .

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