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3 years ago

HELP SABRINA ;) ?!!!

Mathematics

1 answer:

balu736 [363]3 years ago

5 0

Answer:

d) Vessels that are any length

Step-by-step explanation:

MSDs can be defined fully as Marine

Sanitation Devices. Marine Sanitation Devices are devices in the shape of a tank that is used for storing and treating of waste materials when marine vessels e.g. boats are on sea.

It is very inappropriate, unhygienic and illegal to dump waste materials at sea because this could cause harm to the aquatic life forms at sea. This is the reason why a marine sanitation device is required.

There are three types of MSDs

a) Type I

b) Type II

c) Type III

Marine Sanitation Devices are classified into types based on

1) The length of the vessels in which that are installed on.

2. The method for treating or breaking down the waste materials in the devices.

In the question above, the TYPE III MARINE SANITATION DEVICES CAN BE INSTALLED ON VESSELS THAT ARE ANY LENGTH.

This is because the Type III Marine Sanitation Devices are devices that stops the discharge or expelling of waste materials e.g sewage (whether have been treated or untreated) into the sea.

These type III MSDs is consists mainly of a tank used for holding and storing the waste materials. In this tank as well as other types of methods used for treating the waste which the includes incineration, composting e.t.c. may be found in the tank as well. Even after treating the waste in a Type III MSD, it can't be expelled into the sea , it can only be transferred to the Water Treatment Facility when the marine vessel comes to the seaport for more treatment and appropriate disposal.

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fenix001 [56]

Answer:

f(-2) =2

Step-by-step explanation:

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3 years ago

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rusak2 [61]

Step-by-step explanation:

If x=10

$\tt{ x^2-2(x+5) }$ ⠀

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3 years ago

Two cars are driving towards an intersection from perpendicular directions.

FrozenT [24]

For a better understanding of the solution provided here please find the diagram in the attached file.

In the diagram, A is the intersection. B is the position of the first car and C is the position of the second car. As can be clearly seen, as per the directions given in the question, the cars and the intersection make a right triangle.

The distance between the first car and the intersection is $x$ and the distance between the second car and the intersection is $y$ . The distance between the two cars is depicted by $s$ . As we can see, $s$ is the hypotenuse of the right triangle. At the given instance the distances are 8 meters and 6 meters respectively. Thus, by the Pythagorean Theorem the hypotenuse will be:

$s=\sqrt{8^2+6^2}= \sqrt{100}=10$ ...............(Equation 1)

Now, we know that at any instant the Pythagorean Theorem holds and so we will have, in general:

$s^2=x^2+y^2$

Now, implicitly differentiating the above formula with respect to time, we get:

$2s\frac{ds}{dt}=2x \frac{dx}{dt}+2y \frac{dy}{dt}$

This can be further simplified by dividing both the sides by the common factor 2 as:

$s\frac{ds}{st}=x \frac{dx}{dy}+y\frac{dy}{dt}$ .................(Equation 2)

As we can see from the questions and the diagram, $\frac{dx}{dt}=-2 m/s$ and $\frac{dy}{dt}=-9 m/s$ . The negative sign is there because the distances y and x are reducing as the cars approach the intersection.