Let
x--------> the degree of difficulty of the dive
we know that
1) The highest and the lowest scores are dropped
so
highest scores=
lowest scores=
the remaining scores=![[7.5, 8.0, 7.0, 7.5, 7.0]](https://tex.z-dn.net/?f=%20%5B7.5%2C%208.0%2C%207.0%2C%207.5%2C%207.0%5D%20)
2) Find the total of the remaining scores
![=[7.5+8+7+7.5+7]\\ =37](https://tex.z-dn.net/?f=%20%3D%5B7.5%2B8%2B7%2B7.5%2B7%5D%5C%5C%20%3D37%20)
3) The total of the remaining scores is multiplied by the degree of difficulty of the dive
so

4) This product is multiplied by .6 to determine the final score
![[37*x]*0.6=77.7\\ 22.2*x=77.7\\ x=3.5](https://tex.z-dn.net/?f=%20%5B37%2Ax%5D%2A0.6%3D77.7%5C%5C%2022.2%2Ax%3D77.7%5C%5C%20x%3D3.5%20)
therefore
the answer is
the degree of difficulty of the dive is 
Answer:
See explanation
Step-by-step explanation:
If the mystery number rounds to 700, then it has 3 digits before decimal points and two digits after decimal point.
Hence, the mystery number is

The digit in the tenth place is double the digit in the tens place, so

If b = 1, then d = 2
If b = 2, then d = 4
If b = 3, then d = 6
If b = 4, then d = 8
The difference between the digit in the hundreds place and the ones place is 3, so

The first digit can be only 7, because b < 5 and the number rounds to 700. So
If a = 7, then c = 4
All possible answers:
714.2e
724.4e
734.6e
744.8e,
where e is an arbitrary digit from 0 to 9.
There are 40 possible numbers which match the situation.
Answer:
x = 1/2, −1/2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
16
Step-by-step explanation:
All you have to do 4/9 of 36 which is 16.
Hope this helps!!
Answer:
Fail to reject.
Step-by-step explanation:
For a goodness of fit test the decision rule is:
If the calculated value of the test statistic is more than the right tailed critical value of chi-square, then the null hypothesis will be rejected.
The hypothesis for a goodness of fit test is:
<em>H</em>₀: There is no differences between the observed and expected frequencies.
<em>Hₐ</em>: There is a significant differences between the observed and expected frequencies.
The computed value of the test statistic is, 6.079.
The critical value of chi-square is 9.488.
Calculated test statistic < Critical value
6.079 < 9.488
Thus, the null hypothesis was failed to rejected.