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4 years ago

Rewrite equation to solve for m 4n-6m=-2

Mathematics

1 answer:

hram777 [196]4 years ago

7 0

Answer:

Step-by-step explanation:

4n - 6m = - 2 Subtract 4n from both sides.

4n-4n - 6m = -2-4n

-6m = - 2 - 4n Divide by - 6

-6m/-6= -2/-6 -4n/-6 Do the division

m = 1/3 + 2n/3

The signs change because each term has 2 minus signs. 2 minus signs make a plus. Or both minus signs cancel.

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(-3)^3 please answer

bagirrra123 [75]

Answer:

-27

Step-by-step explanation:

-3*-3=9 and then 9*-3 = -27

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3 years ago

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The difference between two trinomials is 5x2 + 11x − 16. If one of the trinomials is 3x2 − 2x + 7, then which expression could b

vredina [299]

Answer:

$2x^2+13x-23$

Step-by-step explanation:

The first trinomial is

$3x^2-2x+7$

Let the other trinomial be P.

Then

$P+3x^2-2x+7=5x^2+11x-16$

We make P the subject to obtain,

$P=5x^2-3x^2+11x+2x-16-7$

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3 years ago

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3 years ago

Find m/AEB A. 10 B. 70 C. 110 D. 170

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4 years ago

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago