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baherus [9]
4 years ago
7

Rewrite equation to solve for m 4n-6m=-2

Mathematics
1 answer:
hram777 [196]4 years ago
7 0

Answer:

Step-by-step explanation:

4n - 6m = - 2              Subtract 4n from both sides.

4n-4n - 6m = -2-4n

-6m = - 2 - 4n             Divide by - 6

-6m/-6= -2/-6 -4n/-6  Do the division

m = 1/3 + 2n/3

The signs change because each term has 2 minus signs. 2 minus signs make a plus. Or both minus signs cancel.

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(-3)^3 please answer
bagirrra123 [75]

Answer:

-27

Step-by-step explanation:

-3*-3=9 and then 9*-3 = -27

6 0
3 years ago
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The difference between two trinomials is 5x2 + 11x − 16. If one of the trinomials is 3x2 − 2x + 7, then which expression could b
vredina [299]

Answer:

2x^2+13x-23

Step-by-step explanation:

The first trinomial is

3x^2-2x+7

Let the other trinomial be P.


Then


P+3x^2-2x+7=5x^2+11x-16


We make P the subject to obtain,

P=5x^2-3x^2+11x+2x-16-7


We simplify to obtain,

P=2x^2+13x-23


Hence the other trinomial is 2x^2+13x-23






7 0
3 years ago
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Find the missing side of the figure that was scaled up from the original
Varvara68 [4.7K]
What is that other number to the right of the red and I can answer it
5 0
3 years ago
Find m/AEB<br><br> A.<br> 10<br> B.<br> 70<br> C.<br> 110<br> D.<br> 170
Paul [167]
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5 0
4 years ago
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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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