Let 'x' be the problems worth 2 points.
Let 'y' be the problems worth 3 points.
Since, there are 38 total problems.
So,
(equation 1)
x = 38-y
Since, a perfect score is 100 points.
So,
(equation 2)
Substituting the value of 'x', we get



y = 24
x+y = 38
x = 38-24 = 14
So, 14 problems are worth 2 points and 24 problems are worth 3 points.
D I’m in highschool Ik for sure
1. 2,359,412; 2,937,158; 3,356,000; 3,368,742
2. 2,009,604; 2,009,832; 2,103,425; 2,112,300
I don’t think this is algebra 2 but ok
37
I used the formula (32°F − 32) × 5/9 = 0°C (but ofc replaced the numbers with 99)
Yeah and i rounded 98.6 to 99. 99 Fahrenheit is 37.2222... so i rounded it down to 37. So i think the answer is 37.
First way
arcsin(1/4) means that 1/4 sin of the angle.
sin(α)=1/4
sin²α+cos²α=1
(1/4)²+cos²α=1
cos²α=1-1/16 =15/16
cosα=+/-(√15)/4
<span>Second way
</span>
sin(α)=1/4 =opposite leg/hipotenuse
cos(α)=adjacent leg/hypothenuse
adjacent leg =√(hypotenuse²- Opposite²)=√(16-1)=√15
cosα=+/-√15/4
For one value of sinα, possible 2 values of cosα.