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sergey [27]
4 years ago
8

) for which there is an institutional network connected to the internet. Suppose that the average object size is 750000 bits and

that the average request rate from the institutions browser to the origin servers is 20 requests per second. What's the traffic intensity (bits/s of traffic)/link bandwidth of the access link. Put the percent in decimal form.
Computers and Technology
1 answer:
Mila [183]4 years ago
6 0

Answer:

The answer is ''37500''

Explanation:

Given value:

Average object size =750000

Origin servers = 20\ \ \frac{request}{second}

Traffic intensity=?

formula:

\bold{\text{Traffic intensity}= \frac{\text{Average object size}}{\text{Origin servers}}}\\

                         =\frac{750000}{20}\\\\=\frac{75000}{2}\\\\= 37500

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Write a function called ReverseLetters that takes an input phrase consisting of a single word and reverses the sequence of lette
ad-work [718]

Answer:

# The function reverseLetter is defined

def reverseLetter(received_word):

   # The first letter of the word is assigned to a variable using index 0

   firstLetter = received_word[0]

   # The last letter of the word is assigned to a variable using index of

   # string length - 1

   lastLetter = received_word[len(received_word) - 1]

   # reverse letters in between first and last letter is defined as

  # empty string

   reverseBetween = ""

   # A counter is defined to control the loop during the reversal

   # counter value is 2 from the length of the received string

   # The 2 is for the first and last letter remove

   counter = len(received_word) - 2

   # The while loop start

   while counter >= 1:

       # The reverseBetween string is concatenated with corresponding

      # index of received word

       # The index is from high to low since the process is string reversal

       reverseBetween += received_word[counter]

       # The value of counter is decremented

       counter -= 1

   # The reversed string is displayed with no separator

   print(firstLetter, reverseBetween, lastLetter, sep="")    

Explanation:

The code is well commented.

reverseLetter("come") will output cmoe

reverseLetter("welcome") will output wmoclee

reverseLetter("brainly") will output blniary

4 0
4 years ago
WHAT DOES THE SCRATCH CODE BELOW DO?
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Lee purchased a new pc from dell computer's web site. he purchased his product via a(n) ________.
olga55 [171]
A <span>direct distribution channel if I'm not wrong.</span>
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Explanation: Hopefully this helps you. (pls don't report if wrong)

8 0
3 years ago
Read 2 more answers
4.2 code need help plz someone 15 points if u help
Korolek [52]

def func():  

 total = 0

 while True:

   pet = input("What pet do you have? ")

   if pet == "rock":

     return

   total += 1

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func()

We wrapped our code in a function so that whenever the user enters rock, we can simply return and exit the function. If you have any other questions, I'll do my best to answer them.

8 0
4 years ago
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