3 years ago

8 to the power of 2 + 3 ( 36 divided by 6 ) - 2

Mathematics

1 answer:

katen-ka-za [31]3 years ago

7 0

$\huge\boxed{80}$

Let's start off by writing this with symbols. $8^2+3(\frac{36}{6})-2$

Follow the order of operations and start with the exponent. $64+3(\frac{36}{6}-2$

Now, solve the parentheses. $64+3*6-2$

Multiply. $64+18-2$

Add. $82-2$

$\boxed{80}$

You might be interested in

2y = 16x-2 y=8x-1 no solution, infinite solution or one solution ?

Zarrin [17]

No solution to this problem

7 0

4 years ago

HELP PLEASE ON 13- A, B, C Can anyone tell me if the ones I did are right

KiRa [710]

13a.) If you're dividing and the base (in this case the base is 10) is the same, subtract the exponents.
${10}^{7} \div {10}^{5} = {10}^{7 - 5} = {10}^{2}$
13b.) If you're multiplying and the base is the same, then you add the exponents:

${s}^{2} \times {s}^{3} \times s = {s}^{2 + 3 + 1} = {s}^{6}$
13c.) This is similar to 13b:

${6}^{4} \times {6}^{3} \times 6 = {6}^{4 + 3 + 1} = {6}^{8}$