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3 years ago

A rectangle has dimensions of 12 cm long and 10 cm wide what is the area of the rectangle

1 answer:

3 0

The area and the width are known as 60 and 12 respectively. Rearranging that equation above, and plugging the values, one gets the value of the length of the rectangle as 5.

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The points (12,23) and (14,45) lie on a line.<br> What is the slope of the line?

Irina18 [472]

Answer:11

Step-by-step explanation:

so that is easy it is rise over run!!!

y2-y1 over x2-x1!!! look at picture!!!

3 0

2 years ago

Find the circumference given the area = 113.1 ft². Use 3.14 for π as necessary.

olga_2 [115]

The circumference of the circle is 37.68 ft

Step-by-step explanation:

Given,

The area of the circle is 113.1 sq ft

To find the circumference of the circle we need to find the radius of the circle first

Formula

The area of circle with radius r is = π $r^{2}$ sq unit

The circumference of circle with radius r is = 2πr unit

Let us take the radius of the circle is r ft

According to the problem,

π $r^{2} =113.1$

or, $r^{2} = \frac{113.1}{3.14}$

or, $r^{2} = 36.01 = 36 (approx)$

or, r = $\sqrt{36}$

or, r = 6

Now,

The circumference of the circle is 2×3.14×6 ft = 37.68 ft

5 0

2 years ago

Read 2 more answers

In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what i

swat32

Apply the Pythagoras Theorem

${c }^{2} = {a}^{2} + {b}^{2}$
${9 }^{2} = {7}^{2} + {b}^{2}$
$81 = 49+ {b}^{2}$
$81 - 49 = {b}^{2}$
$32= {b}^{2}$
Take square root of both sides

$b = \sqrt{32}$
$b = 4 \sqrt{2}$

5 0

3 years ago

Read 2 more answers

I need help please don't know this

SashulF [63]

Answer:

9 is the right answer

Step-by-step explanation:

I. If c = - 4 and d = 10

then $\frac{1}{4}(-4^{3} + 10^{2} )$

= $\frac{1}{4}(-64 + 100)$

= $\frac{1}{4}(36)$

= 9

Hope that help :D

6 0

3 years ago

What is m∠Q ?

ddd [48]

Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.

7 0

2 years ago

Read 2 more answers