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2 years ago

PLS HELPFirst answer- (5,0) (10,0)Second answer- (0,1//20) (0,20)

Mathematics

1 answer:

Julli [10]2 years ago

7 0

X-intercept mean y=0

2/5x+1/10(0)=2

2/5x=2

X= 5

X-intercept = (5,0)

Y-intercept means x= 0

2/5(0)+1/10y=2

1/10y=2

y=20

Y-intercept = (0,20)

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Tom and jasper have the same percentage of blue marbles in their bags of marble tom has 5 blue marbles and 20 total marbles jasp

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8 of them are not blue

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2 years ago

Solve the equation y=2x^2-x-6 using the quadratic formula show the steps to solving

saul85 [17]

Answer:

$x1 = 2 \\ x2 = - \frac{3}{2}$

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{1 + - \sqrt{ {( - 1)}^{2} - 4(2)( - 6) } }{2(2)} \\ x = \frac{1 + - \sqrt{1 + 48} }{4} \\ x = \frac{1 + - \sqrt{49} }{4} \\ x = \frac{1 + - 7}{4} \\ \\ x1 = \frac{1 + 7}{4} = \frac{8}{4} = 2 \\ x2 = \frac{1 - 7}{4} = - \frac{6 }{4} = - \frac{3}{2}$

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3 years ago

The ratio of your monthly allowance to your friend’s monthly allowance is 5 : 3. If your friend received a monthly allowance of

Sever21 [200]

Answer:

i recience 10 dollars

Step-by-step explanation:

5 0

2 years ago

Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

5 0

2 years ago

If t represent the number of tickets purchased for a baseball game, which scenario is modeled by the equation, 32.50t + 5 = 28.7

AnnyKZ [126]

Answer:

(B) The price for the lower level is $32.50 a ticket, plus $5.00 for a discounted parking pass. The middle-level tickets are $28.75 each, plus $20.00 for a parking pass.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

PLS HELPFirst answer- (5,0) (10,0)Second answer- (0,1//20) (0,20)​

PLS HELPFirst answer- (5,0) (10,0)Second answer- (0,1//20) (0,20)