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2 years ago

A roofer measures a run of 4 feet for each 2 feet of rise on a roof. what is the pitch, or slope, of the roof

Mathematics

1 answer:

kobusy [5.1K]2 years ago

6 0

Rise/Run=2/4= 1/2, the answer would be 1/2.

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A. Objeto que cae. La fórmula

iragen [17]

Answer:

Step-by-step explanation: La fórmula de la caída libre, teniendo a la altura como valor dado, sería:

donde h es la altura y g la gravedad.

Solución

h=100 metros

g=9.8m/s^2

se sustituye en la fórmula

dando como resultado

th=4.52 segundos de caída libre

8 0

2 years ago

Match the reasons to the statements in the proof. Given: m 1 + m 5 = 180° m 1 + m 4 = 180° Prove: | | 1. m∠1 + m∠5 = 180° and m∠

Arte-miy333 [17]

Step-by-step explanation:

Let set up the two column proof

Statements. Reasons

1. m 1+ m∠5 = 180° and m∠1 + m∠4=180° Given

2. 2. m∠1 + m∠5 = m∠1 + m∠4. Substitution

3.m∠5 = m∠4. Subtraction Property of Equal

4.is Parallel to Given. 4.If alternate interior angles equal, then lines are ||.

8 0

1 year ago

Solve the system of equations by substitution.<br> X=-4y<br> X+5y=2

Eduardwww [97]

X= -4y let this be equation 1
x+5y=2 let this be equation 2

substitute equation 1 in 2

-4y + 5y = 2

y=2

substitute the value of y in equation 1

x= -4y
x= -4(2)
x= -8

5 0

2 years ago

A rocket is launched from the top of a 55-foot cliff with an initial velocity of 138 ft/s.

melisa1 [442]

For this case we have that the equation that describes the height is:

$h = -16t ^ 2 + vt + c$

Where,

v: initial speed

c: initial height

Substituting values we have:

$h = -16t ^ 2 + 138t + 55$

Then, to find the time, we use the quadratic formula:

$t =\frac{-b +/-\sqrt{b^2 - 4ac} }{2a}$

Substituting values we have:

$t =\frac{-138 +/-\sqrt{138^2 - 4(-16)(55)} }{2(-16)}$

Rewriting:

$t =\frac{-138 +/-\sqrt{19044 + 3520} }{-32}$

$t =\frac{-138 +/-\sqrt{22564}}{-32}$

$t =\frac{-138 +/-150.21}{-32}$

We discard the negative root because we want to find the time.

We have then:

$t =\frac{-138 -150.21}{-32}$

$t =\frac{-288.21}{-32} \\t=9$

Answer:

D. $0 = -16t^2 + 138t + 55; 9 s$

3 0

2 years ago

On a standardized exam, the scores are normally distributed with a mean of 300 and a standard deviation of 50. Find the z-score

Radda [10]

Answer:

z = -3

Step-by-step explanation:

<u>Use the formula for z-score</u>

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{150-300}{50}\\ \\z=\frac{-150}{50}\\ \\z=-3$

This tells us that the person's score of 150 puts him/her 3 standard deviations below the mean of 300.

5 0

1 year ago