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Sedaia [141]
2 years ago
14

Dan's dog-walking job pays $15 per hour. His job as a car-wash attendant pays $400 each week. Dan wants to know how many hours h

e needs to spend walking dogs to earn more than $520 in a week.
Mathematics
2 answers:
KengaRu [80]2 years ago
5 0

Answer:

if his car-wash job gives him $400 then he should only work 8 hours walking dogs to reach 520. Though it says to earn 'more than $520' so maybe 9hrs?

Step-by-step explanation:

He already has $400, which leave $120. 120 divided by 15 equals 8.

drek231 [11]2 years ago
5 0

Answer:

Dan needs to walk dogs for at least 9 hours in order to earn more than $520 a week.

Step-by-step explanation:

Since his car wash attendant job pays $400 a week then you can subtract that from your final revenue.

$520-$400=$120

Now, to find out how many hours he has to walk dogs for in order to earn more than $520, you need to know some basic multiplication so...

$15×8=$120

...but he needs to earn MORE than $520 so...

$15×9=$135

$400+$135=$535.

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A bus on a regular schedule takes 3 1/4 hours to reach its destination. The express bus takes 2 1/2 hours to make the same trip.
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3 years ago
Read 2 more answers
olice response time to an emergency call is the difference between the time the call is first received by the dispatcher and the
yan [13]

Answer:

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 7.2 minutes and a standard deviation of 2.1 minutes.

This means that \mu = 7.2, \sigma = 2.1

For a randomly received emergency call, find the probability that the response time is between 3 and 9 minutes.

This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3.

X = 9

Z = \frac{X - \mu}{\sigma}

Z = \frac{9 - 7.2}{2.1}

Z = 0.86

Z = 0.86 has a pvalue of 0.8051

X = 3

Z = \frac{X - \mu}{\sigma}

Z = \frac{3 - 7.2}{2.1}

Z = -2

Z = -2 has a pvalue of 0.0228

0.8051 - 0.0228 = 0.7823

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

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Answer:

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