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FromTheMoon [43]
3 years ago
15

Find the area of the given figure​

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

You need to sum the area of the rectangle with the one of the semi circle:

Rectangle: 14*10 = 140mm

Semi-circle = (1/2) * pi * 14*14 = approx 308mm

Total area = 140 + 308 = approx 448mm

Step-by-step explanation:

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Answer:

Step-by-step explanation:

This is a pretty basic related rates problem. I'm going to go through this just like I do in class when I'm teaching it to my students.

We see we have a snowball, which is a sphere. We are talking about the surface area of this sphere which has a formula of

S=4\pi r^2

In the problem we are given diameter, not radius. What we know about the relationship between a radius and a diameter is that

d = 2r so

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S=4\pi(\frac{d}{2})^2 which simplifies to

S=4\pi(\frac{d^2}{4}) and a bit more to

S=\pi d^2 (the 4's cancel out by division). Now that is a simple equation for which we have to find the derivative with respect to time.

\frac{dS}{dt}=\pi*2d\frac{dD}{dt} Now let's look at the problem and see what we are given as far as information.

The rate at which the surface area changes is -3.8, and we are looking for \frac{dD}{dt}, the rate at which the diameter is changing, when the diameter is 13. Filling in:

-3.8=\pi(2)(13)\frac{dD}{dt} and solving for the rate at which the diameter is changing:

-\frac{3.8}{26\pi}=\frac{dD}{dt} and divide to get

\frac{dD}{dt}=-.459\frac{cm}{min} Obviously, the negative means that the diameter is decreasing.

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How do I find the area of a trapezoid?​
konstantin123 [22]

Answer:

Step-by-step explanation:

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Use the distributive property to find the product.
VladimirAG [237]

A Is your answer :D        

W^2 + 2W + 3

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(3.14)(21.98)(21.98)

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