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lara [203]
3 years ago
6

Check inequality m> -2

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0
For this there is a dotted line going through -2 on the graph and the shading is on the right side of the grid so -2,-1, and every positive number.
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The equation of this graph is
san4es73 [151]
Is this what you need or? Y= 1/4x +3
4 0
3 years ago
Read 2 more answers
I need help with 19-25. PLEASE NEED ASAP!!
lorasvet [3.4K]

Answer:

That's just -6

Step-by-step explanation:

The 19 is smaller then the 25 so you gotta go back to the negatives, so do 25 - 19 but add a negative.

3 0
3 years ago
21. In the figure given below, AC is parallel to DE. Find the valuesof xy and z and hence find the 2DBE.
algol13

Answer:

X= 50°

Y= 70°

Z= 30°

BDE= 30°

2BDE= 60°

Step-by-step explanation:

(2x -70 )+z+(2x+20)=180...(sum of angle on a straight line)

2x -70 = BDE... alternate angles

Y + (2x-70)+(50+x-20) = 180...(sum of angles in a triangle)

X-20 = z ... alternate and opposite angles

(2x -70 )+z+(2x-+20)=180

2x-70 + x-20 +2x +20= 180

5x -70= 180

5x = 250

X= 50°

X-20 = z

50-20= z

30° = z

2x -70 = BDE

2(50) -70 = BDE

100-70 = BDE

30°= BDE

Y + (2x-70)+(50+x-20)

Y + 100-70 +50 +50 -20 = 180

Y + 200-90=180

Y= 70°

2BDE = 2*30

2BDE= 60°

8 0
3 years ago
The cost of 5 tables exceeds the cost of 8 chairs by Rs.150. Write the linear equation in two variables
Levart [38]

Answer:

The  linear equation in two variables is 5u - 8v  = 150 .

Step-by-step explanation:

As given

The cost of 5 tables exceeds the cost of 8 chairs by Rs150 .

Let us assume that the cost of one table be u .

Let us assume that the cost of one chairs be v .

Than the equation becomes

5u + 150 = 8v

Simplify the above equation

5u - 8v  = 150

Therefore the  linear equation in two variables is 5u - 8v  = 150 .




3 0
3 years ago
A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n
mafiozo [28]

Answer:

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

\hat p=\frac{40}{120}=0.333 estimated proportion of strawberries damaged

p_o=0.25 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0
3 years ago
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