Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
3) 36
2) 55
Step-by-step explanation:
We have to place the numbers in order from least to greatest.
3) 23, 26, 26, 32, 32, 36, 50, 52, 52, 52, 59,
4) 40, 42, 49, 54, 62, 67, 67, 70, 95
The more is the the difference between the lowest and highest values.
95-40=55
Answer:
The answer is 'No Solution'
Answer:
Step-by-step explanation:
- (18u^2 - 142u - 11) ÷ (u - 8)
- 18u^2 - 142u - 11 =
- 18u^2 - 8*18u + 2u - 11 =
- 18u(u - 8) + 2u - 16 + 5 =
- 18u(u - 8) + 2(u - 8) + 5 =
- (18u + 2)(u - 8) + 5
- (18u^2 - 142u - 11) ÷ (u - 8) = 18u + 2 + 5/(u - 8)
