Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546 .
Answer: 9.30918
Step-by-step explanation:
The options can be rewrited as follow:
A. 5<4
B. 5<5
C. 5<4
D. 4<-5
∴ Answer is none of the above.
Unless perhaps you have written down the question incorrectly.
Answer:
A = 40/n
Therefore, she gave each friend 40/n ounces of jelly beans.
Step-by-step explanation:
Given;
Total amount of jelly beans To = 3 pounds = 3×16 ounces = 48 ounces
Total amount kept for family Ta = 8 ounces
Total amount given to friends = Ti
Number of friends = n
Amount given to each friend = A
Ti = To - Ta
A = Ti/n = (To-Ta)/n
A = (48 - 8)/n
A = 40/n
Therefore she gave each friend 40/n ounces of jelly beans.
Answer:
A and D are wrong because if j is the point being focused on the letter should be in the middle of the other letters