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iVinArrow [24]
4 years ago
15

3/5 of a certain class left on a field trip. 1/3 of the students who stayed behind did not want to go on the field trip (all the

others did want to go). When another vehicle was located, 1/2 of the students who did want to go on the field trip but had been left behind were able to join.What fraction of the class ended up going on the field trip?
Mathematics
1 answer:
Tom [10]4 years ago
8 0

Answer:

11/15

Step-by-step explanation:

In this kind of problem, it is cool to always have a value for the total number of students. We can choose any arbitrary value for this. So let’s say the total number of students is 120.

Now we were told 3/5 left for the field trip. The number that left corresponds to 3/5 of 120 = 72 students. The number that didn’t go on the field trip is thus 120 - 72 = 48 students.

Now what do we know again? 1/3 of those who stayed behind didn’t want to go. The number that didn’t want to go is thus 1/3 of 48 = 16. The number that wanted to go but didn’t leave with the first batch is thus 48 - 16 = 32

Now, a bus came along and half of those who wanted to go but were left behind joined. This is equal to a value of 1/2 * 32 = 16

Now the question is what fraction of the class left for the field trip. All we need do is add the first batch to the second batch and divide the result by the total number of students. The addition of both yields = 72 + 16 = 88 students.

The fraction that left was thus 88/120 = 11/15

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Steve took a 300 mile business trip and decided to travel by car. He drove the speed limit for half the trip until an accident o
svetoff [14.1K]

Answer:

He traveled for 2.5 hrs at 54 mi/hr

He traveled for 3 hrs at 61 mi/hr

------------------------------

check:

(1) +d+=+54t+

(1) +d+=+54%2A2.5+

(1) +d+=+135+ mi

3 0
3 years ago
The manager of a theater noted that for every 10 admission tickets sold, the theater sells 3 bags of popcorn at $2.25 each, 4 so
Shalnov [3]

Answer:

$1.475 is the average amount of snack sales per ticket sold.

Step-by-step explanation:

We are given the following in the question:

Number of popcorn bags sold = 3

Cost of  a popcorn bag = $2.25

Total cost of popcorn bag = 2.25\times 3 = $6.75

Number of soda sold = 4

Cost of  a soda = $1.50

Total cost of soda = 1.50\times 4 = $6.00

Number of candy bars sold = 2

Cost of  a candy bar = $1.00

Total cost of candy bars =  1.00\times 2 = $2.00

Total sales =

Total cost of popcorn + Total cost of soda + Total cost of candy bar

= 6.75 + 6 + 2\\=\$14.75

\text{Average} = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Average amount of snack sales per ticket sold =

\dfrac{\text{Total sales}}{\text{Number of tickets}} = \dfrac{14.75}{10} = 1.475

Thus, $1.475 is the average amount of snack sales per ticket sold.

5 0
3 years ago
George is considering two different investment options. The first offers 7.4% per year simple interest on the initial deposit. T
pentagon [3]

Answer:

Part A) \$12,220.00

Part B) \$12,134.08

Part C) The simple interest investment is better than the compounded  interest investment at the end of three years.

Part D)  see the explanation

Step-by-step explanation:

Part A) Determine the value of the simple-interest investment at the end of three years

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=3\ years\\ P=\$10,000\\r=7.4\%=7.4/100=0.074

substitute in the formula above

A=10,000(1+0.074*3)

A=10,000(1.222)

A=\$12,220.00

Part B) Determine the value of the compound-interest investment at the end of three years

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=3\ years\\ P=\$10,000\\r=6.5\%=6.5/100=0.065\\n=4

substitute in the formula above

A=10,000(1+\frac{0.065}{4})^{4*3}  

A=10,000(1.01625)^{12}  

A=\$12,134.08

Part C) Which investment is better over the first three years?

Compare the two investment

\$12,134.08 < \$12,220.00

The compounded  interest investment is less than the simple interest investment

therefore

The simple interest investment is better than the compounded  interest investment at the end of three years

Part D) How would you advise George to invest his money if he is unsure how long he’ll keep the money in the account?

we have

A=10,000(1+0.074t)  ----> simple interest formula as a function of the time t

A=10,000(1.01625)^{4t}   ----> compound interest formula as function of the time t

Look to the attached graph below

The red line represents the simple interest investment

The blue curve represents the compounded interest investment

After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest

After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

therefore

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

4 0
3 years ago
What is the exterior angle measure of a regular 18-gon
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Answer:

d = 97 - 80

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Step-by-step explanation:

7 0
3 years ago
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