x^2 + y^2 + 2x - 6y + 1 = 0
x^2 +2x + 1 + y^2 - 6y = 0
x^2 + 2( x × 1) + 1^2 + y^2 - 2(y×3) + 3^2 -3^2 =0
(x+1)^2 + (y-3)^2 = 3^2
comparing with circle equation
(x-a)^2 + (y - b)^2 = r^2
where (a , b) is centre of circle.
so we get center of circle is
(-1, 3)
5 cookies - 2 cookies = 3 cookies
Start by distributing -5x into x then into -3y. So -5x times x equals -5x^2( -5x squared), then -5 times -3y, equals 15xy so your answer is -5x^2 + 15xy.
Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
You need to put the Answers and picture/problem before asking someone to answer it.
