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Flura [38]
3 years ago
11

A:

Mathematics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

A CAT = A DOG

A TAC = A GOD

A ACT = A ODG

A ATC = A OGD

A TCA = A GDO

A CTA = A OGD

Step-by-step explanation:

You can mix them up as long as the other similar side is the same as you mix them up. Ik it sounds confusing but please see the pattern

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What is the distance between (5, -1) and (5,-4)<br><br> 1 unit<br> 3 unit<br> 4 unit<br> 5 unit
Anton [14]

Answer:

3 units  

Step-by-step explanation:

8 0
3 years ago
3 4/7 minus 2 1/5 by rounding to the nearest half
mylen [45]

Answer:

1 \frac{13}{35}

Step-by-step explanation:

3 \frac{4}{7} -  2 \frac{1}{5}

you can solve for the fractions first, but you have to give them a common denominator

\frac{20}{35}- \frac{7}{35}

= \frac{13}{35} which is in simplest form

then solve for the whole numbers

3-2=1

therefore, the answer is 1 \frac{13}{35}

6 0
3 years ago
F represents the fee (in dollars) for climbing d meters.
Grace [21]

Answer:

$12

Step-by-step explanation:

when d = 0,  F = 110

when d = 100, F = 110 + (0.12 x 100) = 122

when d = 200, F = 110 + (0.12 x 200) = 134

etc.

Therefore, increase in price for every 100 meters climbed = 134 - 122 = 122 - 110 = 12

3 0
3 years ago
Pretest: Unit 1
Alex_Xolod [135]

A vertical line that the graph of a function approaches but never intersects. The correct option is B.

<h3>When do we get vertical asymptote for a function?</h3>

Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going  to infinity or -ve infinity (from either side of   x = a) as x goes near a, and is not defined at   x = a, then at that point, there can be constructed a vertical line  x = a and it will be called as vertical asymptote for f(x) at   x = a

A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.

Hence, the correct option is B.

Learn more about Vertical Asymptotes:

brainly.com/question/2513623

#SPJ1

3 0
2 years ago
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
4 years ago
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