Selma uses a jogging trail that runs through a park near her home. The trail is a loop that is 3/4 of a mile long. On Monday, Se
lma ran the loop in 1/6 of an hour. What is Selma’s unit rate in miles per hour for Monday’s run? In this activity, you will use the common denominator method to calculate a unit rate that involves fractions.
Part A
According to the question, the unit rate is to be expressed in which units?
Answer: miles per hour
Part B
Now, write Selma’s jogging rate as a complex fraction. A complex fraction is one whose numerator, denominator, or both are fractions. Be sure to include units in your answer.
Answer: 3/4 / 1/6 miles/hour.
part c submit without answer oof
Part D
Rewrite the fractions using the least common denominator (LCD) you found in part C.
Answer: 2/12
I need answer for E
Part E
Rewrite the complex fraction as a division problem that reads left to right.
i need answer for F
Part F
To divide 9/12 by 2/12, answer this question: How many sets of 2/12 are in 9/12? Use the model representing the fraction 9/12 to help you answer the question. (Hint: Think about grouping the blue boxes into pairs.)
I need answer for G
Part G
To divide two fractions with common denominators, divide the first numerator by the second numerator, ignoring the denominators. Rewrite this division problem as the division of two integers.
i need answer for H
Part H
Solve the division problem to find Selma’s unit rate in miles per hour. Write your final answer as a mixed number.
i need answer for I
Part I
Express your answer to the problem as a sentence. Be sure to include the correct units.
im giving 100 points but please answer and no guessing im marking as brainliest please answer quickly
The readings are normally distributed with mean 0° and standard deviation 1°. It means that the readings follows a standard normal distribution, so the reading that corresponds to the 98th percentile is equal to the z value that fulfill with:
P(Z<z)=0.98
Then, using the standard deviation table, we have that the z value is equal to 2.06. it means that the reading that separate the bottom 98% from the top 2% is equal to 2.06°