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vazorg [7]
3 years ago
11

**NEED HELP!!! 

Mathematics
1 answer:
Zanzabum3 years ago
5 0

Answer:

The answer was 170.28

Step-by-step explanation:

I took the test. You can see explanation with MrEquation's answer on the same question at 9395039 (the numbers at the end of the URL)

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Please and thank you
algol [13]

Answer:

the last one

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the justification for each step in the solution of the equation?<br><br> 4(4x+6)−7=77−4x
zepelin [54]

Answer:

20x + 17 = 77    --> Addition Property of Equality:

You are adding (Addition Property) 4x to both sides of the equal sign (Equality).

20x = 60           --> Subtraction Property of Equality:

You subtracted (Subtraction Property) 17 from both sides of the equal sign (Equality).

x = 3                  --> Division Property of Equality:

You divided (Division Property) 20 from both sides of the equal sign (Equality) to completely isolate the variable x.

~

6 0
3 years ago
Write an equation of the line that passes through the point (2, 3) and is perpendicular to the line x = -1.
Sedbober [7]

Answer:

B)Y=3

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
zzz [600]

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

The uncertainty formula for a division is given by:

\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

Hence, the relation between the uncertainty in the average velocity is 0.426

4 0
3 years ago
On a certain​ exam, Tony corrected 20 papers and found the mean for his group to be 70. Alice corrected the remaining 10 papers
son4ous [18]

Answer:

The mean of the combined group is 76.67 ≈ 77

Step-by-step explanation:

  1. The sum of the grades in Tom's group is 20×70 = 1400
  2. The sum of grades in Alice's group is 10×90=900
  3. The sum of gradees in the combined group is =1400+900=2300
  4. Then the mean grade of the combined group is \frac{2300}{30}=76.67

where

  • 2300 is the sum of the all grades in the combined group
  • 30 is the total number of people in the group
4 0
3 years ago
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