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2 years ago

11

**NEED HELP!!!

1 answer:

Zanzabum2 years ago

5 0

Answer:

The answer was 170.28

Step-by-step explanation:

I took the test. You can see explanation with MrEquation's answer on the same question at 9395039 (the numbers at the end of the URL)

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7 divided by 86 using long division

pogonyaev

The answer is about 12.2

6 0

3 years ago

CosA×cos2A+sinA×sin2A=cos (2A-A)

Aleksandr-060686 [28]

Answer:

csc

A

, as desired!

Step-by-step explanation:

cos

2

A

sin

A

+

sin

2

A

cos

A

,

=

cos

2

A

cos

A

+

sin

2

A

sin

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sin

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cos

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,

=

cos

(

2

A

−

A

)

sin

A

cos

A

,

=

cos

A

sin

A

cos

A

,

=

1

sin

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,

=

csc

A

, as desired!

7 0

2 years ago

PLEASE HELP WILL GIVE BRAINLIEST

emmainna [20.7K]

Pi is defined as the ratio of the circumference of any circle to its diameter. As all circles are similar and therefore proportional in dimensions, pi is therefore always the same for all circles and is constant

3 0

2 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago

A man invest 5,200,part at 4% and the balance at 3%. If his total income for the two investments is $194,how much money did he i

Fed [463]

Let the amount invested at 4% be = x

Let the amount invested at 3% be = y

Given is:

$x+y=5200$ or $x=5200-y$ .... (1)

As, total income for the two investments is $194, so equation is:

$0.04x+0.03y=194$ ....(2)

Putting value of x from (1) in (2)

$0.04(5200-y)+0.03y=194$

$208-0.04y+0.03y=194$

$0.01y=14$

$y=1400$

And x=5200-y

$x=5200-1400=3800$

Hence, money invested at 4% is $3800 and money invested at 3% is $1400

6 0

2 years ago